Hello,
To solve this problem, you can use the Pythagorean Theorem.
It is: a² + b² = c²
If you input the 6 for a and the 10 for c, you get:
6² + b² = 10²
Now, you just have to solve the equation.
36 + b² = 100
b² = 64
b = 8
The missing side is 8.
Good luck,
MrEQ
If u need anything let me k ow I don’t have enough info to answer that
Answer:
1) 0.338
2) 0.4065
3) 0.2555
Step-by-step explanation:
1. The probability that they will lose both contracts is the probability of losing contract 1 and 2 altogether:
The probability of losing contract 1 is: 1 - 0.35 = 0.65
The probability of losing contract 2, given that they lose contract 1 is: 1 - 0.48 = 0.52
The probability of losing both contracts is 0.65*0.52 = 0.338
2. The probability that they win only one contract is the probability they they win contract 1, lose contract 2, plus the probability that they lose contract 2, win contract 1:
0.35*(1-0.73) + (1-0.35)*0.48 = 0.0945 + 0.312 = 0.4065
3. The probability that they win both contract is
0.35 * 0.73 = 0.2555
Straight Horizontal line.