The x-intercepts are: -0.5 and 2.
The addison see to the horizon at 2 root 2mi.
We have given that,Kaylib’s eye-level height is 48 ft above sea level, and addison’s eye-level height is 85 and one-third ft above sea level.
We have to find the how much farther can addison see to the horizon
<h3>Which equation we get from the given condition?</h3>
Where, we have
d- the distance they can see in thousands
h- their eye-level height in feet
For Kaylib
For Addison h=85(1/3)
Subtracting both distances we get
Therefore, the addison see to the horizon at 2 root 2mi.
To learn more about the eye level visit:
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Answer:
0.61
Step-by-step explanation:
Pr (female) = total number of females(n')/Total number of students(n)
Where P(female) = probability of selectinga female
Pr(female) = n'/n................. Equation 1
Given: n = 44 students, n' = 15+12 = 27 females
Substitute into equation 1
Pr(female) = 27/44
Pr(female) = 0.61.
Hence the probability of selecting a female is 0.61
Answer:
Reject H0
Step-by-step explanation:
Given :
H0: The frequencies are equal. H1: The frequencies are not equal
Category f0 A 10 B 30 C 30 D 10
Total f0 = (10 + 30 + 30 + 10) = 80
Expected frequency is the same for all categories :
Expected frequency = 1/4 * 80 = 20
χ² = Σ(observed - Expected)² / Expected
χ² = (10-20)^2 / 20 + (30-20)^2 /20 + (30-20)^2 / 20 + (10-20)^2 / 20
χ² = (5 + 5 + 5 + 5) = 20
Pvalue = 0.00017
Pvalue < α