ΔJKL, sin(JLK)=JK/KL=3/6=0.5
<JKL=30deg.
cos(JLK)=JL/KL
JL=KL*cos(JLK)=6cos(30deg.)
<JLK + <JLM = <MLK
30 + <JLM = 61
<JLM=31deg
in ΔMJL
tan(JLM)=JM/JL
JM=JL*tan(JLM)
=6cos(30deg.)*tan(31deg)
=3.12
When trapezoidal prism undergoes a dilation, the size of the prism changes
The height of the image is 52.2 meters
<h3>How to determine the height of the image?</h3>
The given parameters are:
A1 = 35 m²
A2 = 315 m²
H1 = 5.8 m
To calculate the height of the image, we make use of the following equivalent ratio
A1 : H1 = A2 : H2
So, we have:
35 : 5.8 = 315 : H
Express as fractions
35/5.8 = 315/H
Make H the subject
H = 315 * 5.8/35
Evaluate the product
H = 52.2
Hence, the height of the image is 52.2 meters
Read more about dilation at:
brainly.com/question/3457976
Answer:
Step-by-step explanation:
I think it is liner because it is a straight line no curves
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