T=650mi(hr/50mi)=13 hr
t-1=12 hr
12=650/(50+v)  multiply both sides by 50+v
600+12v=650  subtract 600 from both sides
12v=50  divide both sides by 12
v=25/6 mph
v≈4.17mph
        
             
        
        
        
Well A seems like the most correct answer, the actual purpose of an afterburner is to inject fuel directly into the exhaust stream to increase thrust by as much as 50%. It’s usually used to go supersonic
        
             
        
        
        
Answer:
B
Step-by-step explanation:
Took the test on AP3X
 
        
                    
             
        
        
        
38.5 / 1.25 = 30.8 or 77/2 divide by 5/4 = 154/5 = 30.8
so, the unit rate is 30.8