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timofeeve [1]
3 years ago
11

Which statement explains the property of integer exponents shown in this equation? aman = am + n

Mathematics
2 answers:
harkovskaia [24]3 years ago
4 0

Answer:

D

Step-by-step explanation:

The rule of exponents

a^{m} × a^{n} = a^{(m+n)}

Shows that when 2 powers with the same base are being multiplied then the exponents are added.

lisov135 [29]3 years ago
4 0

Answer:

Step-by-step explanation:

The answer is : To multiply two powers with the same base, add the exponents.

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30/78 simplified is 15/39
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The length of a rectangular field is 3 more than twice the width. the farmer would like to divide the field into four equal encl
nika2105 [10]
Assume w is the width. the length is 3*2w
To fence the whole outside of farm, he needs:
2(w+6w)=14w meters
Also he needs one width and one length for the enclosed pens. Therefore, the total amount of fencing he would need:
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7 0
4 years ago
the following are scores of students:9,7,8,9,7,5,8,10,7,8 and 10. the value of the population variance is 4. true or false?​
DENIUS [597]

Answer:

<h3>yes</h3>

Step-by-step explanation:

yyyyyyyyyyyyyyyyyyyyyy

5 0
3 years ago
4(2x-3) is greater than or equal to 4(x-4)
mylen [45]

Answer:    x ≥ -1

<u>Step-by-step explanation:</u>

4(2x - 3) ≥ 4(x - 4)

8x - 12 ≥ 4x - 16       <em>distributed 4 into 2x - 3</em>

4x - 12 ≥ -16              <em>subtracted 4x from both sides</em>

4x ≥ -4                       <em>added 12 to both sides</em>

 x ≥ -1                        <em>divided both sides by 4</em>


Graph:    -1 -------------→

Interval Notation: [ -1, ∞ )

8 0
4 years ago
Use a table of values with at least 5 values to graph the following function:
34kurt

The given expression :

y=(\frac{1}{2})^x

For coordinates:

put x = 0 then :

\begin{gathered} y=(\frac{1}{2})^0 \\ y=1 \end{gathered}

Coordinate : (x, y) = (0, 1)

Put x= 1 and simplify :

\begin{gathered} y=(\frac{1}{2})^1 \\ y=\frac{1}{2} \\ y=0.5 \end{gathered}

Coordinate : (x, y) = ( 1, 0.5)

Put x = (-2) and simplify :

\begin{gathered} y=(\frac{1}{2})^{-2} \\ y=\frac{1^{-2}}{2^{-2}} \\ y=\frac{2^2}{1^2} \\ y=2^2 \\ y=4 \end{gathered}

Coordinate : (x, y) = ( -2, 4)

Put x = (-3) and simplify :

\begin{gathered} y=(\frac{1}{2})^{-3} \\ y=\frac{1^{-3}}{2^{-3}} \\ y=\frac{2^3}{1^3} \\ y=2^3 \\ y=8 \end{gathered}

Coordinate : (x, y) = (-3, 8)

Substitute x = (-1) and simplify :

\begin{gathered} y=(\frac{1}{2})^x \\ y=(\frac{1}{2})^{-1} \\ y=\frac{1^{-1}}{2^{-1}} \\ y=\frac{2}{1} \\ y=2 \end{gathered}

Coordinate : (x, y) = ( -1, 2)

So, the coordinates are :

The graph is :

4 0
2 years ago
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