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3 years ago

What is a rigid transformation

Mathematics

1 answer:

serg [7]3 years ago

7 0

A rigid transformation is a transformation of the plane that preserves length.

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What is the factored form of x^2-x-2

lisov135 [29]

Answer:

(x-2),(x+1)

Step-by-step explanation:

5 0

3 years ago

Find f(b-2) if f(x) = x^2-6x+1

jasenka [17]

$▪▪▪▪▪▪▪▪▪▪▪▪▪ {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪$

The equivalent expression is ~

$f(b - 2) = {b}^{2} - 10b + 17$

$\large \boxed{ \mathfrak{Step\:\: By\:\:Step\:\:Explanation}}$

Let's evaluate f(b - 2) ~

$f(x) = {x}^{2} - 6x + 1$

$f(b - 2) = (b - 2) {}^{2} -6 (b - 2) + 1$

$\mathcal{ {f(b - 2) = {b}^{2} + 2 {}^{2} - (2 \times b \times 2) - 6b + 12}}$

$f(b - 2) = {b}^{2} + 4 - 4b - 6b + 12 + 1$

$f(b - 2) = {b}^{2} - 10b + 17$

4 0

3 years ago

Read 2 more answers

Rodger has 47 cars . Can he group the cars in more than two ways?

deff fn [24]

First of all, Rodger must be making some serious cash to have 47 cars. Going back to the question, he can not group the cars in more than 2 ways. He can only group it in 1 way, 47 groups of 1. Pls brainliest

4 0

3 years ago

Use the picture for the question and the answer choices:)

Orlov [11]

Parenthesis first 5-2=3.

7^2=49

-3*3=-9

49-9=40.

A is your answer.

8 0

3 years ago

How many ways are there to assign 8 visiting different studetns to one Stony Brook summer course, chossing from Calculus I, Line

Dmitry_Shevchenko [17]

Answer:

56 ways

Step-by-step explanation:

Number of ways is given by n combination r (n!/(n - r)!r!)

n = total number of students = 8, r = the number of summer courses = 3

Number of ways = 8 combination 3 = 8!/(8-3)!3! = 8!/5!3! = 8×7×6×5!/5!×6 = 8×7 = 56 ways

6 0

3 years ago