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3 years ago

Simplify to create an equivalent expression. 19−6(−k+4)

Mathematics

1 answer:

balu736 [363]3 years ago

8 0

Answer:

6k-5

Step-by-step explanation:

19−6(−k+4)

Distribute

19+6k-24

Combine like terms

6k-5

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I need help yall can someone work this out with steps

dimulka [17.4K]

Answer:

STOOPID

Step-by-step explanation:

6 0

3 years ago

A total of 644 tickets were sold for the school play. They were either adult tickets or student tickets. There were 56 fewer stu

DochEvi [55]

Create formulas!

x=number of adult tickets

y=number of student tickets

x+y=644 <em>total sold</em>

56+y=x <em>student was 56 less than adult</em>

Perform substitution

(56+y)+y=644

56+2y=644

2y=588

y=294

Substitute y into the formula we created

x+294=644

x=350

350 adult tickets were sold.

3 0

4 years ago

Read 2 more answers

Insert geometric means in each geometric sequence.

Digiron [165]

Answer:

$\underline{192}, 24, \underline{3}, \underline{\dfrac{3}{8}}, \dfrac{3}{64}$

$\underline{\dfrac{1}8}, \dfrac{1}{4}, \dfrac{1}{2}, \underline{1}$

$81, \underline{27, 9, 3, 1},\dfrac{1}{3}$

Step-by-step explanation:

Given the Geometric sequences:

1. ___, 24, ___, ___, 3/64

2. ___, 1/4, 1/2, ___

3. 81, ___, ___, ___, ___, 1/3

To find:

The values in the blanks of the given geometric sequences.

Solution:

First of all, let us learn about the $n^{th}$ term of a geometric sequence.

$a_n=ar^{n-1}$

Where $a$ is the first term and

$r$ is the common ratio by which each term varies from the previous term.

Considering the first sequence, we are given the second and fifth terms of the sequences.

Applying the above formula:

$ar = 24\\ar^4 = \dfrac{3}{64}$

Solving the above equation:

$r = \dfrac{1}{8}$

Therefore, the sequence is:

$\underline{192}, 24, \underline{3}, \underline{\dfrac{3}{8}}, \dfrac{3}{64}$

Considering the second given sequence:

$ar = \dfrac{1}{4}\\ar^2 = \dfrac{1}{2}\\\text{Solving the above equations}, r = 2$

Therefore, the sequence is:

$\underline{\dfrac{1}8}, \dfrac{1}{4}, \dfrac{1}{2}, \underline{1}$

Considering the third sequence:

$a = 81\\ar^5=\dfrac{1}{3}\\\Rightarrow r = 3$

Therefore, the sequence is:

$81, \underline{27, 9, 3, 1},\dfrac{1}{3}$

5 0

3 years ago

I need help please?!!!!

xeze [42]

Answer: It is true.

Step-by-step explanation:

8 x 8=64

6x8=48

64-48=16

4x12=48

16 is in fact less than 48

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3 years ago

Read 2 more answers

Question 3 of 5

bagirrra123 [75]

Answer: B

Step-by-step explanation:

4 0

3 years ago