All categories

3 years ago

Please helpppppppppp

Mathematics

2 answers:

Lostsunrise [7]3 years ago

8 0

Answer:

see picture above shown

BigorU [14]3 years ago

6 0

Answer:

The answer is -a^2 + 3a +1

Let me know if it's right, this is what I got when I did the problem :)

You might be interested in

Solve the triangle. Round your answers to the nearest tenth.

mixas84 [53]

Answer:

Angles: $\angle A = 43^{\circ}$ $\angle B = 55^{\circ}$ $\angle C = 82^{\circ}$

Sides: $BC = 20$ $AB = 29$ $AC =24$

Step-by-step explanation:

See attachment for complete question

From the attachment, we have:

$AB = 29$

$AC =24$

$\angle C = 82^{\circ}$

Required

Complete the missing side and missing angles

To calculate angle B, we apply sine laws:

$\frac{a}{sinA}=\frac{b}{sinB}=\frac{c}{sinC}$

In this case:

$\frac{AB}{sinC}=\frac{AC}{sinB}$

This gives:

$\frac{29}{sin(82^{\circ})}=\frac{24}{sinB}$

$\frac{29}{0.9903}=\frac{24}{sinB}$

Cross Multiply

$sinB * 29 = 24 * 0.9903$

Divide both sides by 29

$sinB = \frac{24 * 0.9903}{29}$

$sinB = 0.8196$

Take arcsin of both sides

$B = sin^{-1}(0.8196)$

$B = 55^{\circ}$

So:

$\angle B = 55^{\circ}$

To solve for the third angle, we make use of:

$\angle A + \angle B + \angle C = 180^{\circ}$

This gives:

$\angle A + 55^{\circ} + 82^{\circ} = 180^{\circ}$

$\angle A + 137^{\circ}= 180^{\circ}$

$\angle A = 180^{\circ}- 137^{\circ}$

$\angle A = 43^{\circ}$

Hence, the angles are:

$\angle A = 43^{\circ}$ $\angle B = 55^{\circ}$ $\angle C = 82^{\circ}$

To calculate the length of the third side, we apply cosine law

$BC^2 = AB^2 + AC^2 - 2*AB*AC*cosA$

$BC^2 = 29^2 + 24^2 - 2*29*24*cos(43^{\circ})$

$BC^2 = 841+ 576 - 1392*cos(43^{\circ})$

$BC^2 = 841+ 576 - 1392*0.7314$

$BC^2 = 841+ 576 - 1018.11$

$BC^2 = 398.89$

Take the square root of both sides

$BC = \sqrt{398.89$

$BC = 19.9722307217$

$BC = 20$

5 0

3 years ago

How do i do this???????????????????????????????????

Karo-lina-s [1.5K]

Answer:

The y-intercept is (0, -6).

Step-by-step explanation:

The question is asking you to find the equation of the line that passes through the point (7, 1) and is parallel to line j, which means that the line has the same slope as line j.

To find the slope of line j, you would use the slope formula: $\frac{y_2-y_1}{x_2-x_1}$ .

Use the points on line j: (4, 1), (-3, -6). Substitute in -6 for $y_2$ and 1 for $y_1$ . Substitute -3 for $x_2$ and 4 for $x_1$ .
$\frac{(-6)-(1)}{(-3)-(4)} \rightarrow \frac{-7}{-7} = 1$
The slope of line j is 1, therefore the equation of the line we are writing will also have a slope of 1 since they must be parallel.

To write the equation of the line, use the point-slope formula because we are given the two things in the name of the formula---a point that the line passes through (7, 1) and the slope of the line (1).

Point-slope form is $y-y_1=m(x-x_1)$
Substitute 1 for $y_1$ , 1 for m, and 7 for $x_1$ .
$y-(1)=1(x-(7))$
Simplify: y - 1 = 1(x - 7)
Distribute 1 inside the parentheses.
y - 1 = x - 7
Add 1 to both sides of the equation.
y = x - 6

The question wants you to find the y-intercept of the equation. To find the y-intercept, make x = 0.

y = (0) - 6
Subtract 0 - 6.
y = -6

A point is shown as (x, y). We made x = 0 and found that y = -6, so if you substitute these values into (x, y) the y-intercept will be (0, -6).

5 0

4 years ago

Send help, and fast...

AysviL [449]

It’s a I took the quiz e

6 0

2 years ago

Transforming an image by____changes the size, but not the shape of the image.

gtnhenbr [62]

Answer:

Dilation

Step-by-step explanation:

7 0

3 years ago

There are 185 deer in a state park. The population is increasing at the rate of 16% per year. Enter a

stich3 [128]

Answer:

Approximately 3.4 years more or less

Step-by-step explanation:

If we represent this exponential growth as P=185(1.16)^n where n is the number of years passed and P is the population, then:

P=185(1.16)^n

305=185(1.16)^n

1.65=1.16^n

log₁.₁₆(1.65)=log₁.₁₆(1.16^n)

3.37=n

So the deer population will reach 305 in approximately 3.4 years.

4 0

3 years ago