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Mathematics

2 answers:

Lostsunrise [7]3 years ago

8 0

Answer:

see picture above shown

BigorU [14]3 years ago

6 0

Answer:

The answer is -a^2 + 3a +1

Let me know if it's right, this is what I got when I did the problem :)

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What are the coordinates of the hole in the graph of the function f(x) ?

Vinvika [58]

ANSWER

$(3, \infty )$

EXPLANATION

The given function is

$f(x) = \frac{ {x}^{2} - 9}{x - 3}$

When we plug in x=3 into this function, we obtain,

$f(3) = \frac{0}{0}$

This means that the function is discontinuous at x=3.

We need to simplify the function to obtain,

$f(x) = \frac{(x - 3)(x + 3)}{(x - 3)}$

This implies that,

$f(x) = x + 3$

The graph this function is a straight line that is continuous everywhere.

To graph

$f(x) = \frac{ {x}^{2} - 9}{x - 3}$
we draw the graph of

$f(x) = x + 3$
and leave a hole at x=3.

See diagram in attachment.

Hence the coordinates of hole is

$(3, \infty )$

6 0

3 years ago

Solve (x + 6)/x - 4) = -16 0 (-12. 22) 0 1-4. 2) O {-4. 6)

Snowcat [4.5K]

Answer:

$3\frac{7}{17}$

Step-by-step explanation:

$\frac{(x + 6)}{(x - 4)} = - 16 \\ \\ x + 6 = - 16(x - 4) \\ x + 6 = - 16x + 64 \\ x + 16x = 64 - 6 \\ 17x = 58 \\ x = \frac{58}{17} \\ x = 3\frac{7}{17} \\$