1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
sergeinik [125]
3 years ago
5

A rectangle has side length of 6 and 15.A second rectangle is drawn proportional to the first rectangle.Which of the following c

ould be the length of the second rectangle?select all that apply
A)12and30
B)9and18
C)16and25
D)8and20
E)10and25
Mathematics
1 answer:
noname [10]3 years ago
8 0
I do not know the answer so use ur dang brain dumb ahhhhhh
You might be interested in
25 points to anybody who can solve this pls!
Svetach [21]

Answer:

Q' (2,4)

R' (3,1)

S' (5,3)

Step-by-step explanation:

When reflected across x-axis, the x-values stay the same but y-values change signs. Because you count how many points till the reflection line then same amount you have to go to the other side. But since it is saying x-axis, the reflection line is on x=0 so you just change the sign.

6 0
2 years ago
Read 2 more answers
Please help me! Pic included! ;) :p
saul85 [17]
Here you go!! Hope it helps !!

5 0
3 years ago
Review the table of values for function g(x).
Serga [27]

Answer: C

Step-by-step explanation:

im guessing, so if wrong please let me know

6 0
2 years ago
The junior varsity football team score 23 points in last Saturday's game they score the combination of seven point touchdowns in
frutty [35]

Answer:

  2 touchdowns, 3 field goals

Step-by-step explanation:

The number of touchdowns cannot be more than 3, so it is relatively easy to find the solution by trial and error.

  23 is not divisible by 3, so 0 touchdowns is not a solution

  23 -7 = 16 is not divisible by 3, so 1 touchdown is not a solution

  23 -14 = 9 is divisible by 3, so 2 touchdowns and 3 field goals is a solution

  21 -21 = 2 is not divisible by 3, so there is only one solution.

7 0
3 years ago
A circular swimming pool has a radius of 28ft. There is a path all the way around the pool that's 4ft wide. A fence is going to
Natalka [10]

Answer:

Therefore 200.96 ft.of fencing are needed to go around the pool path.

Step-by-step explanation:

Given, a circular swimming pool has a radius of 28ft. There is a path all the way around the pool. The width of the path 4 ft.

The radius of the outside edge the pool path is

= Radius of the pool + The width of the path

= (28+4) ft

= 32 ft.

To find the length of fencing, we need to find the circumference of outside the pool path.

Here r= 32 ft

The circumference of outside edge of the pool path

=2\pi r

=(2\times 3.14 \times 32) ft

=200.96 ft.

Therefore 200.96 ft.of fencing are needed to go around the pool path.

3 0
3 years ago
Other questions:
  • The measures of the angles of a triangle are in the ratio 2:4:9 find the measures of all three angles
    15·1 answer
  • Little Benny Franklin has $1.25 all in pennies in a jar. He decides to save 21 pennies every week and add them to the jar. In on
    5·2 answers
  • . Первый мастер может выполнить задание,
    6·1 answer
  • You are making 5 Autumn Classic bouquets for your friends. You have $610 to spend and want 24 flowers for each bouquet. Roses co
    11·1 answer
  • The U.S. quarter has a mass of 5.67 g and is approximately 1.55 mm thick.How many quarters would have to be stacked to reach 575
    12·1 answer
  • An employee spent 60 minutes responding to 8 email message ,how much time did the employer spend responding to each email messag
    12·2 answers
  • 9y= 5/7<br> solve as a fraction
    12·2 answers
  • What is x? I need help T^T
    11·2 answers
  • Help im giving brainlies.
    5·2 answers
  • Use the graph below to answer the question that:
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!