Y = 2x-6
Just move the y to the other side (add y so it gets pushed to the right) then subtract the six from the right to the left side.
Given:
Data Set: 60 items
Median: 25
lower quartile or Q1: 21
upper quartile or Q3: 42
IQR = Q3 - Q1 = 42 - 21 = 21
The DISTRIBUTION IS SKEWED TO THE RIGHT.
distance between median and Q1: 25 - 21 = 4
distance between Q3 and median: 42 - 25 = 17
Since the distance between Q3 and median is greater than the distance between the median and Q1, the distribution is skewed to the right.
<h3>Given:</h3>
<h3>To find:</h3>
- The approximate volume of the given sphere.
<h3>
Solution:</h3>

Let's substitute the values according to the formula.
Let's solve!


Now, well have to round off to the nearest hundredth.

<u>Hence,</u><u> </u><u>the</u><u> </u><u>volume</u><u> </u><u>of</u><u> </u><u>the</u><u> </u><u>given</u><u> </u><u>sphere</u><u> </u><u>is</u><u> </u><u>523.6</u><u> </u><u>cubic</u><u> </u><u>units</u><u>.</u>
Note: If your using π as π you'll get this answer.
8.10/2 + 2.3 = 46 total area is 46