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Bad White [126]
3 years ago
13

What is the axis of symmetry and vertex? y=-3x2-24x-42

Mathematics
1 answer:
sasho [114]3 years ago
8 0
The axis is 8

Symmetry
Is 1(-)-
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URGENT - Use 1.7 as the value of 3. What is the area of equilateral triangle ABC? sq mi
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Hope this helps Use 1.7 as the value<span> of </span>square<span> root of </span>3<span> what is the are od </span>equilateral<span> of </span>triangle abc<span>? The base is 12 </span>miles<span> </span>
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3 years ago
Please Help!!!
algol [13]
f\left(\dfrac\beta2\right)=\sin\dfrac\beta2

Recall the half-angle identity:

\sin^2\dfrac\beta2=\dfrac{1-\cos\beta}2\implies\sin\dfrac\beta2=\pm\sqrt{\dfrac{1-\cos\beta}2}

So in order to find f\left(\dfrac\beta2\right), we only need to know the value of \cos\beta. But there are two possible values. To decide which to take, we use the given information: we know that \beta lies in quadrant III, which means \pi, so \dfrac\pi2, which places \dfrac\beta2 in quadrant II. In this quadrant, the sine of angle is positive, and so

\sin\dfrac\beta2=\sqrt{\dfrac{1-\cos\beta}2}

\beta is an angle of a ray whose terminal point, \left(-\dfrac13,y\right) lies on the circle x^2+y^2=1. The x-coordinate is all we need to know in order to find that \cos\beta=-\dfrac13. So,

\sin\dfrac\beta2=\sqrt{\dfrac{1-\left(-\frac13\right)}2}=\sqrt{\dfrac46}=\dfrac{\sqrt2}{\sqrt3}=\dfrac{\sqrt6}3
6 0
3 years ago
Identify the rule for the pattern below which is 5,10,8,13,11,16,14,19,17,22
Andreyy89

Answer:

Step-by-step explanation:

for odd terms

first term=5

c.d.=8-5=3

odd terms are given by 5+3(n-1)=2+3n

for even terms

first term=10

c.d.=13-10=3

even terms are given by 10+3(n-1)=7+3n

8 0
3 years ago
Marcus is making cookies. The recipe says 214 cups of flour are needed for each batch. Marcus wants to make 3 batches of cookies
Valentin [98]

Answer:

642 Cups of Flower

214 × 3 = 642


8 0
3 years ago
Read 2 more answers
D.<br> X= 1<br> 13.<br> Find the vertex: y=-(x+6)² + 2
adelina 88 [10]

Answer:

the vertex of this parabola is at (-6, 2).

Step-by-step explanation:

Compare the given y=-(x+6)² + 2 with the standard vertex form:

                                 y = a(x - h)^2 + k.  We see that

                                  h must be -6 and k must be 2.

Thus the vertex of this parabola is at (-6, 2).

6 0
4 years ago
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