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anastassius [24]
3 years ago
7

If you can bike 15 miles per hour, how long will it take you to bike 5 miles?

Mathematics
2 answers:
RideAnS [48]3 years ago
5 0

Answer:

20 min

Step-by-step explanation:

5 is 1/3 of 15

That means that the time is 1/3 of a hour which is 20 min

Dafna11 [192]3 years ago
3 0

5 miles is 1/3 the distance of 15 miles

if it takes you an hour to go 15 miles it will take you 1/3 the time to go 5 miles.

1 hour (60 minutes) / 3 = 20 minutes

it will take you 20 minutes

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Tempestt graphs a function that has a maximum located at (–4, 2). Which could be her graph?
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the correct answer is C. I just took the test on ed2020

Step-by-step explanation:


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4 years ago
Read 2 more answers
Find the area of the figure below.
Tema [17]

Answer:

42

Step-by-step explanation:

For the square 6 x 5 = 30

For the triangle 6 x 4 x 1/2 = 12

or 6 x 4 ÷ 2 = 12

add them both 12 + 30 = 42

6 0
2 years ago
Toru takes his dog to be groomed. The fee to groom the dog is $70 plus a 10% tip. Is $80 enough to pay for the service and tip?
elena55 [62]

Answer:

yes it is enough

Step-by-step explanation:

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4 0
3 years ago
The equation C = 5 9 F − 160 9 gives the relation between temperature readings in Celsius and Fahrenheit.
Pavel [41]

Step-by-step explanation:

The question is wrong. The correct equation is :

C=\frac{5}{9}F-\frac{160}{9}

We know that the equation gives the relation  between temperature readings in Celsius and Fahrenheit.

Therefore, giving that we know the value in Fahrenheit ''F'' we can find the reading in Celsius ''C''. This define a function C(F) that depends of the variable ''F''.

So for the incise (a) we answer Yes, C is a function of F.

For (b) we need to find the mathematical domain of this function. Giving that we haven't got any mathematical restriction, the mathematical domain of the function are all real numbers.

Dom (C) = ( - ∞ , + ∞)

For (c) we know that the water in liquid state and at normal atmospheric pressure exists between 0 and 100 Celsius.

Therefore the range will be

Rang (C) = (0,100)

Now, we need to find the domain for this range. We do this by equaliting and finding the value for the variable ''F'' :

For C = 0 :

0=\frac{5}{9}F-\frac{160}{9} ⇒ F=32

And for C = 100 :

100=\frac{5}{9}F-\frac{160}{9} ⇒ F=212

Therefore, the domain as relating temperatures of water in its liquid state is

Dom (C) = (32,212)

For (d) we only need to replace in the equation by F=71 and find the value of C ⇒

C=\frac{5}{9}F-\frac{160}{9} ⇒

C=(\frac{5}{9})(71)-\frac{160}{9}

C=\frac{65}{3} ≅ 21.67

C(71) = 21.67 °C

4 0
3 years ago
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