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hodyreva [135]
3 years ago
15

What is the value of 11x^-3 y^-1 for x=-1 and y=2

Mathematics
1 answer:
andrey2020 [161]3 years ago
3 0

Answer:

  -11/2

Step-by-step explanation:

Put the numbers into the expression and do the arithmetic.

  11(-1)^{-3}2^{-1}=\dfrac{11}{(-1)^3}\cdot\dfrac{1}{2^1}=\dfrac{-11}{2}

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Use the quadratic formula to find the solutions to the quadratic equation below 2x^2-5x+5=0
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Answer:

x = (5 + i sqrt(15))/4 or x = (5 - i sqrt(15))/4

Step-by-step explanation:

Solve for x:

2 x^2 - 5 x + 5 = 0

Hint: | Using the quadratic formula, solve for x.

x = (5 ± sqrt((-5)^2 - 4×2×5))/(2×2) = (5 ± sqrt(25 - 40))/4 = (5 ± sqrt(-15))/4:

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Hint: | Express sqrt(-15) in terms of i.

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Answer: x = (5 + i sqrt(15))/4 or x = (5 - i sqrt(15))/4

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Step-by-step explanation:

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