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3 years ago

What is the value of 530

Mathematics

1 answer:

Art [367]3 years ago

5 0

Five hundred thirty

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A car traveling 118 miles uses 4 gallons of gas. At this rate, how many miles can it travel using 13 gallons of gas

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12 miles per gallon

Step-by-step explanation:

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If jim gets 100 dollars per month and martha gets 150 how much more would they get in 15 years??

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Jim would get 1500, Martha gets 2250

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Using a pencil, paper, and protractor, or a drawing program, draw an isosceles triangle that has exactly one 50° angle. Use the

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2 years ago

Spencer made a quilt for his cousin's doll. The quilt had a 7x7 array of different color square patches. If each patch is 1 3/4

Damm [24]

Answer:

$\frac{2401}{16}$ square inches

Step-by-step explanation:

Given:

The quilt made by Spencer had a 7×7 array of different color square patches such that each patch is $1\frac{3}{4}$ in long.

To find: the area of the whole quilt

Solution:

Side of each quilt = $7(\frac{3}{4})=7(\frac{7}{4})=\frac{49}{4}$

Quilt is in the form of a square such that area of square is given by $(side)^2$

Therefore, area of quilt = $(side)^2=(\frac{49}{4})^2 =\frac{2401}{16}$ square inches

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4 years ago

The gas law for an ideal gas at absolute temperature T (in kelvins), pressure P (in atmospheres), and volume V (in liters) is PV

JulijaS [17]

Answer:

$\frac{dT}{dt}=3.78^{\circ}K/min$

Step-by-step explanation:

We have to calculate the time derivative of T=PV/nR with P and V variable and n and R constants. This is:

$\frac{dT}{dt} =\frac{d\frac{PV}{nR}}{dt}=\frac{1}{nR}\frac{d(PV)}{dt}$

What we have to do is the derivative of a product:

$\frac{d(PV)}{dt}=P\frac{dV}{dt}+V\frac{dP}{dt}$

Substituting, we have:

$\frac{dT}{dt} =\frac{P\frac{dV}{dt}+V\frac{dP}{dt}}{nR}$

where all these values are given since the time derivatives of P and V are their variation rate, using minutes.

We then substitute everything, noticing that already everything is in the same system of units so they cancel out:

$\frac{dT}{dt}=\frac{P\frac{dV}{dt}+V\frac{dP}{dt}}{nR}=\frac{(8atm)(0.16L/min)+(13L)(0.14atm/min)}{(10mol)(0.0821Latm/mol^{\circ}K)}$

And then just calculate:

$\frac{dT}{dt}=3.78^{\circ}K/min$

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3 years ago