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kotykmax [81]
2 years ago
15

Which solid has a greater volume

Mathematics
1 answer:
Triss [41]2 years ago
5 0

Answer:

The volume of cylinder and the volume of a cone, have equal volume measurements. So, the answer is C).

Step-by-step explanation:

Cylinder:

-Use the formula for the volume of a cylinder. Use both the radius and height for the formula in order to solve and get the volume:

V = \pi r^2 h

V = \pi 2^2 6

-Solve:

V = \pi 2^2 6

V = \pi \times 2^2 \times 6

V = \pi \times 4 \times 6

V = \pi \times 24

V = 24\pi \approx 75.39

--------------------------------------------------------------------------------------------------------

Cone:

-Use the formula for the volume of a cone and the radius and height for the formula and solve the formula to get the volume:

V = \frac{1}{3} \pi r^2h

V = \frac{1}{3} \pi 3^28

-Solve:

V = \frac{1}{3} \pi 3^28

V = \frac{1}{3} \times \pi \times 3^2 \times 8

V = \frac{1}{3} \times \pi \times 9 \times 8

V = \frac{1}{3} \times \pi \times 72

V = \frac{1}{3} \pi \times 72

V = 24\pi \approx 75.39

-So, according to the volume of a cylinder and the volume of a cone, They both have the same volume.

Cylinder: 75.39 ft^3

Cone: 75.39 ft^3

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Step-by-step explanation:

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The circle below has a radius of 3 units . Find the area of the circle. Use 3.14 for π.
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Answer:

28.26 units

Step-by-step explanation:

We know the radius of the circle is 3 units, so we'll end up plugging that into the formula.

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2 years ago
15x^2 + 41x + 28 <br><br>STEP BY STEP ANSWER PLSSS​
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Answer:

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Step-by-step explanation:

15x^2 +41x+28

Factor the expression by grouping. First, the expression needs to be rewritten as 15x^2 +ax+bx+28. To find a and b, set up a system to be solved.

a+b=41

ab=15×28=420

Since ab is positive, a and b have the same sign. Since a+b is positive, a and b are both positive. List all such integer pairs that give product 420.

1,420

2,210

3,140

4,105

5,84

6,70

7,60

10,42

12,35

14,30

15,28

20,21

Calculate the sum for each pair.

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2+210=212

3+140=143

4+105=109

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10+42=52

12+35=47

14+30=44

15+28=43

20+21=41

The solution is the pair that gives sum 41.

a=20

b=21

Rewrite 15x^2 +41x+28 as (15x^2 +20x)+(21x+28).

(15x^2 +20x)+(21x+28)

Factor out 5x in the first and 7 in the second group.

5x(3x+4)+7(3x+4)

Factor out common term 3x+4 by using distributive property.

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