Answer:
y = -2x + 3 is the required equation
Step-by-step explanation:
From the graph we will get two ordered pairs
If we see that When x=0 then y=3 and when x = 1 then y=1
Now from this we can find the slope of the Graph
So slope of graph = (y2 - y1) / (x2-x1)
=(1-3) / (1-0)
=-2
So
Slope = m = -2
Now the equation is
y = mx + b
We have to find the value of b
as we have two ordered pairs we can take any of it to find the value of b because line passes through those points
taking (0,3) as a point
y= mx + b
put values
3 = -2*(0) + b
so
b=3
Now the equation of the line in this form is
y = mx + b
which is
y = -2x + 3
Answer:
1. R
2. Match the year with the price. For example, 2006 should have a line directly on 15.
3. A (The first number on each row is the second number multiplied by 4)
4. C
5. A
MAKE SURE TO DOUBLE-CHECK JUST IN CASE!
Answer:
p=3/8, q=1/2
Step-by-step explanation:
Please mark as brainliest
Answer:
see below
Step-by-step explanation:
Each point moves to half its previous distance from P. It is probably easier to count grid squares on the graph than it is to do the math on the coordinates.
If you're doing the math on the coordinates, it is convenient to use P = (0, 0), then multiply each of the coordinates of A, B, and C by 1/2. For example:
A' = (1/2)A = (1/2)(8, 4) = (4, 2)
Answer:the car was traveling at a speed of 80 ft/s when the brakes were first applied.
Step-by-step explanation:
The car braked with a constant deceleration of 16ft/s^2. This is a negative acceleration. Therefore,
a = - 16ft/s^2
While decelerating, the car produced skid marks measuring 200 feet before coming to a stop.
This means that it travelled a distance,
s = 200 feet
We want to determine how fast the car was traveling (in ft/s) when the brakes were first applied. This is the car's initial velocity, u.
Since the car came to a stop, its final velocity, v = 0
Applying Newton's equation of motion,
v^2 = u^2 + 2as
0 = u^2 - 2 × 16 × 200
u^2 = 6400
u = √6400
u = 80 ft/s
