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3 years ago

If a+b+c=16 and a^2+b^2+c^2=90 then find the value a^3+b^3+c^3-3abc

1 answer:

3 0

$(a+b+c)^2=a^2+b^2+c^2+2(ab+bc+ca)\\(16)^2=90+2(ab+bc+ca)\\256-90=2(ab+bc+ca)\\166/2=ab+bc+ca\\83=ab+bc+ca\\a^3-b^3-c^3-3abc=(a+b+c)(a^2+b^2+c^2-ab-bc-ca)\\(a+b+c)(a^2+b^2+c^2-(ab+bc+ca))\\16(90-(83))\\16(7)\\=112$

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The radius of a circle with an area of 60 square centimeters is represented by the expression √60/π centimeters. What is another

monitta

Answer:

r= 2 √(15/π)

Step-by-step explanation:

Given that :

Area of circle =60sq cm

radius=√60/π

$Area=\pi r^2\\60=\pi r^2\\\\\sqrt{\frac{60}{\pi}}=r\\\\\sqrt{\frac{15\times 4}{\pi}}=r\\2\sqrt{\frac{15}{\pi}}=r$

Hence the radius can be written as 2 √(15/π)

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3 years ago

Decrease <br>133 in the ratio 7:2

love history [14]

Answer:

Step-by-step explanation

2/7× 133=38

6 0

3 years ago

two girls went shopping and spent $334. one girls spent $16 more thent the other girl did. how much did each spend

Taya2010 [7]

I will try my best to assist you with your question ,

First we must divide the amount by 2

334/2 = 167

Now we add 16

167 + 16=183

So, the girl spent $183

Wow, she is spoiled!

Hope I helped!

Good Luck!

3 0

3 years ago

If line AD is a tangent to circle B at point C, and m ABC = 55°, what is the measure of BAD?

nikdorinn [45]

Answer:

145°

Step-by-step explanation:

There are a couple of ways you can get there:

1. ∠ACB is a right angle, 90°. Hence, ∠BAC is the complement of ∠ABC, so is ...

... ∠BAC = 90° -∠ABC = 90° -55° = 35°

Then, ∠BAC and ∠BAD are a linear pair, so total 180°. That makes ∠BAD the supplement of ∠BAC, so ...

... ∠BAD = 180° -35° = 145°

2. ∠BAD is the exterior angle at A for the triangle ABC. It will have a measure that is the sum of the opposite interior angles: given ∠ABC = 55° and right angle ACB = 90°.

... ∠BAD = 55° +90° = 145°

8 0

3 years ago

Help me get the answer

drek231 [11]

This is hard- DHJDHSJS

3 0

3 years ago