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4vir4ik [10]
4 years ago
5

HELP MEEE no guessing

Mathematics
1 answer:
faltersainse [42]4 years ago
8 0
Answer:


25/24


Explanation:

I did the math can u tell me if I got it right tho.



Here’s the way I did in steps

Step1: convert the fractions in to decimals
Step2:divide the decimals
Step3: convert the answer choices into decimals
Step4: Find your answer

Ik ik ik I’m big brain

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A data set includes 103103 body temperatures of healthy adult humans having a mean of 98.998.9degrees°f and a standard deviation
dangina [55]

Answer:

98.9-2.62\frac{0.65}{\sqrt{103}}=98.73    

98.9+2.62\frac{0.65}{\sqrt{103}}=99.07    

So on this case the 99% confidence interval would be given by (98.73;99.07)    

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X=98.9 represent the sample mean for the sample  

\mu population mean (variable of interest)

s=0.65 represent the sample standard deviation

n=103 represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=103-1=102

Since the Confidence is 0.99 or 99%, the value of \alpha=0.01 and \alpha/2 =0.005, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.005,102)".And we see that t_{\alpha/2}=2.62

Now we have everything in order to replace into formula (1):

98.9-2.62\frac{0.65}{\sqrt{103}}=98.73    

98.9+2.62\frac{0.65}{\sqrt{103}}=99.07    

So on this case the 99% confidence interval would be given by (98.73;99.07)    

6 0
3 years ago
Read 2 more answers
Need some help, please. : )<br><br> Not sure how to answer this in a formula. : /
yaroslaw [1]

Answer:

No

Step-by-step explanation:

It is a solution to the first equation, but not the second equation.

4 0
3 years ago
280(370-w)+135w=83,000
vekshin1

Answer:

w=4120/29

Step-by-step explanation:

7 0
3 years ago
hi do I have this answer right? I just need someone help me out with this question so I can get the right answer
Kobotan [32]
I belive his answer is wrong B/c the graph does not even start near 310 the first to bars make it to 50 and 150 so even if u add the two together it would only be 200 so, the answer would be B
6 0
3 years ago
You made a square card. The card did not fit in the envelope so you trimmed it. You trimmed 4 inches from the length and 5 inche
ludmilkaskok [199]

Answer:

The original dimensions of the card were 9 inches length and 9 inches width

Step-by-step explanation:

Let x be the original length and width of the card in inches (remember that it was squared originally). The exercise says that the area of the new width, with dimensions x-4 and x-5 is 20 square inches, therefore

(x-4)*(x-5) = 20

x²-9x+20 = 20

x²-9x = 0

x*(x-9) = 0

x = 0 or x = 9

Since x must be positive, then it cant be 0, thus, x has to be 9. The original dimensions of the card were 9 inches length and 9 inches width.

7 0
4 years ago
Read 2 more answers
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