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Rina8888 [55]
3 years ago
11

How many sides does a regular polygon have if each exterior angle measures 72 degrees?

Mathematics
2 answers:
snow_lady [41]3 years ago
7 0
I think you are supposed to divide the sum of the interior angles of the polygon (360 degrees) by the exterior angles of the polygon (72 degrees). When you do this: 360 / 72 = 5 sides.

This would be a pentagon.
damaskus [11]3 years ago
7 0

Answer: 5 sides.


Step-by-step explanation:

We know that the total sum of all exterior angles of a regular polygon = 360°

If each exterior angle measures 72 degrees.

Then the number of sides of the regular polygon

n=\frac{360^{\circ}}{\text{measure of each exterior angles}}=\frac{360^{\circ}}{72^{\circ}}=5

Therefore,  the regular polygon has 5 sides if each exterior angle measures 72 degrees.

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step-by-step explanation: the increase = 204 - 120

increase = 84

percent increase = 84/120

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3 years ago
Find the sum of (x + 5) and (2x + 3)
Genrish500 [490]
What you can do is subtract 1x from each side 
Then you subtract 3 from each side
Then it tells you x=2
Always put what you think x is back into the problem and see if it works out

Example on how you do it:
(x+5)=(2x+3)
5=(x+3)
2=x
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3 years ago
Whats the difference between a sequence and a series?
snow_tiger [21]

Answer:

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3 years ago
Question 4 ( i-Ready )
Bogdan [553]

Answer:

Step-by-step explanation:

Note that the two equations are equivalent.

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Every shared point is a solution. Since there are infinitely many points on a line, and these lines share every point, there are infinitely many solutions.

5 0
3 years ago
Mr. Smith is flying his single-engine plane at an altitude of 2400 feet. He sees a cornfield at an angle of depression of 30º. W
Svet_ta [14]

Answer:

Height of the fighter plane =1.5km=1500 m

Speed of the fighter plane, v=720km/h=200 m/s

Let be the angle with the vertical so that the shell hits the plane. The situation is shown in the given figure.

Muzzle velocity of the gun, u=600 m/s

Time taken by the shell to hit the plane =t

Horizontal distance travelled by the shell =u

x

t

Distance travelled by the plane =vt

The shell hits the plane. Hence, these two distances must be equal.

u

x

t=vt

u Sin θ=v

Sin θ=v/u

=200/600=1/3=0.33

θ=Sin

−1

(0.33)=19.50

In order to avoid being hit by the shell, the pilot must fly the plane at an altitude (H) higher than the maximum height achieved by the shell for any angle of launch.

H

max

=u

2

sin

2

(90−θ)/2g=600

2

/(2×10)=16km

4 0
3 years ago
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