The geometric rule for the nth term of the geometric sequence for which a1 =−6 and a5=−486 is -6 × 3^(n - 1)
<h3>The nth term of a geometric sequence</h3>
First term, a1 = -6
Fifth term, a5 = -486
a5 = ar^(n - 1)
-486 = -6 × r^(5-1)
-486 = -6r⁴
r⁴ = -486 / 6
r⁴ = 81
r = 4√81
r = 3
Geometric rule:
nth term = ar^(n-1)
nth term = -6 × 3^(n - 1)
Learn more about geometric sequence:
brainly.com/question/24643676
#SPJ1
Answer:
C
Step-by-step explanation:
(2,-5) move up three steps is (2, -2). if you draw it on a paper(and draw lines to connect them), you can see that they form a right triangle. apply a²+b²=c² and you should get 3²+2²=(√13)²
Answer:
Step-by-step explanation:
Using the Foil method
you multiply x times x and get 
Then you multiply -4 times X and get -4x
Then you multiply -3 times X and get -3x
then you add -4 and -3 together and get -7x
Lastly you multiply -4 and -3 and get 12
And there you have it
Look at pic for work, all answers and work is listed
