32.5 % of lab are wireless devices
<em><u>Solution:</u></em>
Given that there was a total of 30 computers and the computer lab is removing 3 broken computers and adding 13 wireless devices
Now we can first find out total number of computers and devices in lab
total number of computers and devices in lab = 30 computers - 3 + 13 wireless devices
total number of computers and devices in lab = 30 - 3 + 13 = 40
So there are 40 computers and wireless devices in lab
<em><u>To find: what percent of the lab are wireless devices</u></em>
So we have to find what percent of 40 is 13
Let "a" be the required percent
a % of 40 = 13

32.5 % of of lab are wireless devices
The answer is : 
Here are the steps below to help you! ^^
Answer:
I'm not really,
sure but I think non linear
Step-by-step explanation:
sorry if I'm wrong
Using the z-distribution, it is found that the margin of error is of 0.059.
We are given the standard deviation for the population, hence the <em>z-distribution</em> is used.
<h3>What is the margin of error for a z-confidence interval?</h3>
It is given by:

In which:
is the population standard deviation.
In this problem, the parameters are:
.
- Confidence level of 0.90, hence, using a z-distribution calculator, the critical value is z = 1.645.
Then:



The margin of error is of 0.059.
You can learn more about the z-distribution at brainly.com/question/12517818