Question

Solve the equation on the interval [0, 2π).

Answer 1

$\cos x+2\cos x\sin x=\cos x(1+2\sin x)=0$

$\cos x=0$ in the given interval when $x=\dfrac\pi2,\dfrac{3\pi}2$.

$1+2\sin x=0\implies \sin x=-\dfrac12$ when $x=\dfrac{7\pi}6,\dfrac{11\pi}6$.

Answer 2

Answer: -(sqrt 3/2)

Step-by-step explanation: