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Ahat [919]
3 years ago
13

What is the interquartile range (IQR) of the numbers below? 1, 2, 3, 3, 4, 4, 4, and 6

Mathematics
2 answers:
Serggg [28]3 years ago
8 0

Answer: 2

Step-by-step explanation:

The IQR is when you subtract the 3rd quartile which is 4 and the 1st quartile which is 2, so 4-2= 2. Hopefully I did this correct.

sineoko [7]3 years ago
4 0

Answer: 2.5

First, lets find the median. In this case, its 3.5

Next, find the median of the numbers below the median, and the median of the numbers above the median.

The median of the lower numbers is 2.5

The median of the upper numbers is 5

Now simply find the difference.

5 - 2.5 = 2.5

Hope this helps you!

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Newborn babies: A study conducted by the Center for Population Economics at the University of Chicago studied the birth weights
Fed [463]

Answer:

a) 615

b) 715

c) 344

Step-by-step explanation:

According to the Question,

  • Given that,  A study conducted by the Center for Population Economics at the University of Chicago studied the birth weights of 732 babies born in New York. The mean weight was 3311 grams with a standard deviation of 860 grams

  • Since the distribution is approximately bell-shaped, we can use the normal distribution and calculate the Z scores for each scenario.

Z = (x - mean)/standard deviation

Now,

For x = 4171,  Z = (4171 - 3311)/860 = 1  

  • P(Z < 1) using Z table for areas for the standard normal distribution, you will get 0.8413.

Next, multiply that by the sample size of 732.

  • Therefore 732(0.8413) = 615.8316, so approximately 615 will weigh less than 4171  

 

  • For part b, use the same method except x is now 1591.    

Z = (1581 - 3311)/860 = -2    

  • P(Z > -2) , using the Z table is 1 - 0.0228 = 0.9772 . Now 732(0.9772) = 715.3104, so approximately 715 will weigh more than 1591.

 

  • For part c, we now need to get two Z scores, one for 3311 and another for 5031.

Z1 = (3311 - 3311)/860 = 0

Z2 = (5031 - 3311)/860= 2  

P(0 ≤ Z ≤ 2) = 0.9772 - 0.5000 = 0.4772

  approximately 47% fall between 0 and 1 standard deviation, so take 0.47 times 732 ⇒ 732×0.47 = 344.

5 0
3 years ago
Find the area of the right triangle △DEF with the points D (0, 0), E (1, 1), and F.
Tems11 [23]

Answer:

The area of the triangle is  \sqrt{3}

Step-by-step explanation:

Given:

Coordinates D (0, 0), E (1, 1)

Angle  ∠DEF = 60°

△DEF is a Right triangle

To Find:

The area of the triangle

Solution:

The area of the triangle is  = \frac{1}{2}(base \times height)

Here the base is Distance between D and E

calculation the distance using the distance formula, we get

DE  = \sqrt{(0-1)^2 + (0-1)^2}

DE =\sqrt{(-1) ^2 + (-1)^2

DE = \sqrt{1+1}

DE = \sqrt{2}

Base = \sqrt{2}

Height is DF

DF =tan(60^{\circ}) \times DE

DF = \sqrt{3} \times DE

DF = \sqrt{3} \times\sqrt{2}

Now, the area of the triangle is

= \frac{1}{2}({\sqrt{2})(\sqrt{3} \times \sqrt{2})

=\frac{1}{2}({\sqrt{2})(\sqrt{3} \sqrt{2})

=\frac{1}{2}(2\sqrt{3} )

=\sqrt{3}

6 0
3 years ago
Part A: The area of a square is (16x2 − 8x + 1) square units. Determine the length of each side of the square by factoring the a
d1i1m1o1n [39]

Answer:

see below

Step-by-step explanation:

16x^2 − 8x + 1

(4x)^2 -8x +1

Factor

This is a perfect square trinomial

a^2 -2ab +b^2 = (a-b)(a-b)

(4x)^2 -8x +1 = (4x-1) (4x-1)

The area of a square is given by

A = s^2

(4x-1) ^2 = s^2

4x-1 = s

The side length is 4x-1

(81x^2 − 4y^2)

(9x)^2 - (2y)^2

This is the difference of squares

a^2 - b^2 = (a-b) (a+b)

(9x-2) (9x+2)

The area of a rectangle is

A = l*w

(81x^2 − 4y^2)  = (9x-2) (9x+2)

The dimensions are (9x-2) (9x+2)

3 0
3 years ago
Please help pleeaasssee
Ulleksa [173]

Answer:

10

Step-by-step explanation:

just do 4-18 and u get the answer

5 0
3 years ago
Read 2 more answers
What can the reader study to most directly determine the theme of a poem?
harina [27]
The answer will be C. Theme basically means the message of a story.
6 0
3 years ago
Read 2 more answers
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