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3 years ago

Solve the system 3x+y=2 5x-y=8

Mathematics

1 answer:

Citrus2011 [14]3 years ago

3 0

Answer:

x= 5/4 ; y= -7/4

Step-by-step explanation:

I will solve your system by substitution.

(You can also solve this system by elimination.)

3x+y=2;5x−y=8

Step: Solve3x+y=2for y:

3x+y+−3x=2+−3x(Add -3x to both sides)

y=−3x+2

Step: Substitute−3x+2foryin5x−y=8:

5x−y=8

5x−(−3x+2)=8

8x−2=8(Simplify both sides of the equation)

8x−2+2=8+2(Add 2 to both sides)

8x=10

(Divide both sides by 8)

Step: Substitute

forxiny=−3x+2:

y=−3x+2

y=−3(

)+2

−7

(Simplify both sides of the equation)

Answer:

and y=

−7

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$(9x + 17) +2 \times ( 5x + 15 ) + (6x - 12) = 360 \\$

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Collect like terms

$25x + 35 = 360$

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$25x + 35 - 35 = 360 - 35$

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Divide sides by 25

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Thus ;

$RQ \: \: arc =2 \times (5x + 15)$

$RQ \: \: arc = 10x + 30$

$RQ \: \: arc = 10(13) + 30$

$RQ \: \: arc = 130 + 30$

$RQ \: \: arc = 160°$

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2 years ago

In the diagram abc=adb=90, ad=p and dc=q. Use similar triangles to show that x2=pz<br> plzz anyoneee

kramer

Answer:

By comparing the ratios of sides in similar triangles ΔABC and ΔADB,we can say that $x^{2} =pz$

Step-by-step explanation:

Given that ∠ABC=∠ADC, AD=p and DC=q.

Let us take compare Δ ABC and Δ ADB in the attached file , ∠A is common in both triangles

and given ∠ABC=∠ADB=90°

Hence using AA postulate, ΔABC ≈ ΔADB.

Now we will equate respective side ratios in both triangles.

$\frac{AB}{AC}= \frac{AD}{AB}=\frac{BD}{BC}$

Since we don't know BD , BC let us take first equality and plugin the variables given in respective sides.

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Answer:

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Step-by-step explanation:

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<span> 3 x (4 + 5) as (3 x 4) + (3 x 5)
This is the distributive property</span>

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