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eduard
3 years ago
13

Find ten solutions to the linear equation to the linear equation 1/2x+y=5

Mathematics
1 answer:
yuradex [85]3 years ago
7 0

Answer:

(0,5), (2,4), (4,3), (6,2), (8,1), (10,0), (12,-1), (14,-2), (16,-3), (18,-4), and (20,-5)

Step-by-step explanation:

The given linear equation is :

\frac{1}{2} x + y = 5

Or

y =  -  \frac{1}{2} x + 5

Any ordered pair that satisfies this equation is a solution.

When x=0,

y =  -  \frac{1}{2}  \times 0 + 5 = 5

(0,5) is a solution

When x=2,

y =  -  \frac{1}{2}  \times 2+ 5 = 4

(2,4) is a solution.

When x=4,

y =  -  \frac{1}{2}  \times 4+ 5 = 3

(4,3) is a solution;

When x=6:

y =  -  \frac{1}{2} \times 6+ 5 = 2

(6,2).

When x=8,

y =  -  \frac{1}{2}  \times 8 + 5 = 1

Another solution is (8,1)

When x=10,

y =  -  \frac{1}{2}  \times 10 + 5 = 0

(5,0) is a solution

When x=12,

y =  -  \frac{1}{2}  \times 12+ 5 =  - 1

(12,-1) is a solution.

When x=14,

y =  -  \frac{1}{2}  \times 14+ 5 =  - 2

When x=16, we get:

y =  -  \frac{1}{2}  \times 16 + 5 =  - 3

When x=18, we get:

y =  -  \frac{1}{2}  \times 18+ 5 =  - 4

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Step-by-step explanation:

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The graph can be drawn by the placing the points and after translation points becomes A'(-3, -5), B'(-2, 3), C'(1, 4), and D'(0, -5)

<h3>What is quadrilateral?</h3>

It is defined as the four-sided polygon in geometry having four edges and four corners.

We have:

Quadrilateral ABCD with vertices A(2,-3), B(3,5), C(6,6) and D(5,-3)

We can graph it on the coordinate plane as shown in the picture.

After applying the translation (x, y)→(x−5, y−2), the points becomes:

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Learn more about the quadrilateral here:

brainly.com/question/6321910

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