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Romashka-Z-Leto [24]
2 years ago
9

PLEASE HELP

Mathematics
1 answer:
egoroff_w [7]2 years ago
6 0

Answer:

D

Step-by-step explanation:

Passes through the x-axis at r and k

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7x-2=5x+14<br> X=?<br> (step by step needed)
prisoha [69]

Answer:

x = 8

Step-by-step explanation:

Step 1: Subtract 5x from both sides.

  • 7x-2-5x=5x+14-5x
  • 2x-2=14  

Step 2: Add 2 to both sides.

  • 2x-2+2=14+2
  • 2x=16

Step 3: Divide both sides by 2.

  • 2x/2=16/2
  • x=8

Step 4: Check if solution is correct.

  • 7(8)-2=5(8)+14
  • 56-2=40+14
  • 54=54

Therefore, x = 8.

8 0
2 years ago
Read 2 more answers
Help:<br> <img src="https://tex.z-dn.net/?f=1.%5C%20%26x%5E4-61x%5E2%2B900%3D0%20%5C%5C%202.%20%5C%20%26%20x%5E4-25x%5E2%2B144%3
yawa3891 [41]

\bf{1) \  x^4-61x^2+900=0 }

Applying the factorization method, for example:

      \bf{ 0=(x^2)^2-61(x^2)+900=(x^2-36)(x^2-25)}

               \bf{\\ &=(x+6)(x-6)(x+5)(x-5);    }

              \bf{ x_1=6 \quad x_2=-6 \quad \ \ \ x_3=5 \quad x_4=5  }

\bf{2) \  x^4-25x^2+144=0  }

Applying the factorization method:

          \bf{0&=(x^2)^2-25(x^2)+144=(x^2-16)(x^2-9) }

             \bf{ =(x-4)(x+4)(x-3)(x+3); }

            \bf{ x_1=4 \quad x_2=-4 \quad x_3=3 \quad x_4=-3  }

7 0
1 year ago
Can someone please help me answer this Math problem?
kap26 [50]

Answer:

2√2.

Step-by-step explanation:

We use the Pythagoras Theorem:

x^2 = 2^2 + 2^2

x^2 =  8

x = √8

= 2√2.

4 0
3 years ago
How can you use 4s fact to find 7x8? Give the product in your explanation.
Mkey [24]
So 4's facts

we know that 4 times 2=8 and the associative property of multiplication says
a(bc)=(ab)c

so 7(8) (means 7 times 8) means 7((4)(2)) and associative say we can group them and say (7)(4)(2) so (4)((7)(2)) or 4(14) and 4 times 14=56

7 times 8=56
7 0
3 years ago
The radius of the base of the cylinder is 10 centimeters,and its height is 20 centimeters.A cone is used to fill the cylinder wi
Lady_Fox [76]

Answer:

r u wanting the volume for each shape or what?

Step-by-step explanation:

4 0
3 years ago
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