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Romashka-Z-Leto [24]
2 years ago
9

PLEASE HELP

Mathematics
1 answer:
egoroff_w [7]2 years ago
6 0

Answer:

D

Step-by-step explanation:

Passes through the x-axis at r and k

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MatroZZZ [7]

Answer:

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3 years ago
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Select all the values that belong to the solution set of 9 ≤ 6 - y.
Veseljchak [2.6K]
All you have to do is substitute the values in for y to see if they are true.

0: 9 ≤ 6 - 0 = 9 ≤ 6 (FALSE)
3: 9 ≤ 6 - 3 = 9 ≤ 3 (FALSE)
-3: 9 ≤ 6 - -3 = 9 ≤ 9 (TRUE)
-1: 9 ≤ 6 - -1 = 9 ≤ 7 (FALSE)
-6: 9 ≤ 6 - -6 = 9 ≤ 12 (TRUE)
6: 9 ≤ 6 - 6 = 9 ≤ 0 (FALSE)
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So, the values that belong to 9 ≤ 6 - y are -3, -4, and -6.


7 0
3 years ago
3 (x+6) what is the answer ??​
ziro4ka [17]

Answer:

3x+18

Step-by-step explanation:

3 (x+6)

Distribute

3x+3*6

3x+18

4 0
3 years ago
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Let f(x) = √x-5<br><br> Find f^ -1.
iris [78.8K]

Answer:

f^{-1}(x)= x^2 + 5 \,,\,\,x\geq 0

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Use the method of swapping x and y and isolating y.

f(x) = y = \sqrt{x-5}\,,\,\,\,x\geq 5,y\geq0\\\\f^{-1}:x=\sqrt{y-5}\,,\,\,\,y\geq 5, x\geq 0\\x^2 = y-5\\y = x^2 + 5 = f^{-1}(x)\\

Note that domain/range will be swapped as well.

5 0
4 years ago
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