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GuDViN [60]
3 years ago
11

* URGENT* help plz plz plz plz plz plz plz I SPENT FOREVERRRRRRRRRRR

Mathematics
1 answer:
kiruha [24]3 years ago
7 0

answer:

4(2+x) and 8 + 4x

since she memorized those scales for EACH of those four lessons, the answer would be that.

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3n+7 write the first five terms
harkovskaia [24]

Answer:

10

13

15

17

22

Step-by-step explanation:

the first 5 terms will be 1,2,3,4 and 5.

I guess...

6 0
3 years ago
Read 2 more answers
Y=2x+5 and y=3x+11 solve by substitution.
kondaur [170]

Answer:

Answer: x= -6 and y= -7

Step-by-step explanation:

Substitute 2x+5 for y in y=3x+11:

y=3x+11

2x+5=3x+11

2x+5+−3x=3x+11+−3x(Add -3x to both sides)

−x+5=11

−x+5+−5=11+−5(Add -5 to both sides)

−x=6

−x−1=6−1(Divide both sides by -1)

x=−6

Step: Substitute −6 for x in y=2x+5:

y=2x+5

y=(2)(−6)+5

y=−7(Simplify both sides of the equation)

-Source: MathPapa

6 0
3 years ago
On a dessert table there is one cupcake for every 5 cookies . There are 85 cookies for dessert table. how many cupcakes are on t
vredina [299]
I believe it’s 17

85/5=17
7 0
3 years ago
Three cube-shaped boxes are stacked one above the other. The volumes of two of the boxes are 1,331 cubic meters each, and the vo
blsea [12.9K]
The volume of a box with dimensions x by x by x is  x^{3}.

So if we are given the volume V of a cube-shaped box, the side length of thit is \sqrt[3]{V}.

So we calculate the cubic roots of the volumes we have, and we add their heights.

To calculate the cubic root of 729, we can factorize it, and group the perfect cubes together, as follows:

\frac{729}{3}= \frac{600}{3} + \frac{120}{3} + \frac{9}{3}=200+40+3=243

\frac{243}{3}= \frac{240}{3}+ \frac{3}{3}=80+1=81, which we recognize as 3^{4}

so 729=3*3* 3^{4}= 3^{6}= ( 3^{2} )^{3}= 9^{3}

similarly 1,331 can be found to be 11^{3}.

Thus we have 2 boxes with side length equal to 11 m and one with side length equal to 9 m.


Answer: h= 11+11+9 = 31 (meters)



7 0
3 years ago
Read 2 more answers
MATH QUESTION : WORTH 45 PTS
trapecia [35]

y ≤ x − 5

y ≥ −x − 4


This is a check and see type of problem.


if x=5

y ≤ 5 − 5      y≤ 0    

y ≥ −5 − 4     y ≥-9

-9≤ y  ≤ 0

-2 works   so (5,-2) is a solution


if x= -5

y ≤ -5 − 5      y≤ -10    

y ≥ 5 − 4     y ≥1

no solution

Choice B (5,-2)

5 0
3 years ago
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