Use the fomula a_(n)= a_(1)+ d(n-1)
Answer:
100000 pass codes
Step-by-step explanation:
the pass code form is: abcde
a: 10 numbers to choose
b: 10 numbers
c: 10 numbers
d: 10 numbers
e: 10 numbers
so there are 10^5 = 100000 pass codes exist
Answer:
x = 2
y = -3
Step-by-step explanation:
Step 1: Write systems of equation
8x + 7y = -5
x = -3y - 7
Step 2: Solve for <em>y</em>
- Substitute 2nd equation into 1st: 8(-3y - 7) + 7y = -5
- Distribute 8: -24y - 56 + 7y = -5
- Combine like terms: -17y - 56 = -5
- Add 56 to both sides: -17y = 51
- Divide both sides by -17: y = -3
Step 3: Solve for <em>x</em>
- Substitute <em>y</em> to find <em>x</em>: x = -3(-3) - 7
- Multiply: x = 9 - 7
- Subtract: x = 2
Step 4: Check
<em>Plug in x, y into an original equation to verify it's a solution.</em>
2 = -3(-3) - 7
2 = 9 - 7
2 = 2
144??? If your asking what 6 x 24 is 144 is the answer
:D