The answer is C, if I'm wrong text me sometime and please explain it for me
Answer:
16
Step-by-step explanation:
a^2+b^2=c^2
a^2+12^2=20^2
144+a^2=400
a^2=256
a=16
The lest common multiple is 26. If you do multiples of each number
13:13,26
26: 26
Both of their lest common multiples would be 26
<u>Note: The only way to solve this problem is by adjusting the fees to $3.50 and $7.50.</u>
Answer:
<em>1300 children attended the basketball game</em>
Step-by-step explanation:
System of Equations
Let's call:
x = number of children attending the basketball game
y = number of adults attending the basketball game
On a certain night, 1500 people enter the game, thus:
x + y = 1500 [1]
Since each admission fee for children cost $3.50 and $7.50 for adults and it was collected $6050, thus:
3.50x + 7.50y = 6050 [2]
From [1]:
y = 1500 - x
Substituting in [2]:
3.50x + 7.50(1500 - x) = 6050
Operating:
3.50x + 11250 - 7.50 = 6050
-4x = 6050 - 11250
Solving:
x = 1300
1300 children attended the basketball game
