Answer:
22.9 yards
Step-by-step explanation:
Since b² = a² - c² where a = vertex of major axis, 2a = 50 yards the length of the major axis. So , a = 50/2 = 25 yards. c = focus of chamber = 10 yards from center and b = vertex of minor axis.
So, b = ±√(a² - c²)
= ±√(25² - 10²)
= ±√(625 - 100)
= ±√525
= ±22.91 yards
≅ ± 22.9 yards
Since b = length of minor axis from center of chamber = 22.91 yards. So, he should build the whisper chamber 22.9 yards out from the center of the chamber.
4926.25965251
I used a calculator because it makes solving this much easier
The entire race is 1 full race.
One full race is 1.
He ran 3/8 of 1, so he ran 3/8.
He needs to run the rest of the race.
The rest is unknown, so we call it x.
When you add 3/8 to the unknown, you get the full race.
The equation is
x + 3/8 = 1
Change 1 to a denominator of 8.
x + 3/8 = 8/8
Subtract 3/8 from both sides.
x = 5/8
Answer: He still needs to run 5/8 of the race.
X represents the amount of children's tickets
y represents the amount of adult's tickets
8(x+y) = 54
