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3 years ago

Find the mean, median, and interquartile for the data set below.

Mathematics

1 answer:

Charra [1.4K]3 years ago

8 0

Answer:

Mean: About 202.64, original is 202.636363636 Median: 15.5 Interquartile Range: 4

Step-by-step explanation:

Mean explanation: You add up all; of the numbers and divide the answer by how many numbers there is which would be 11.

Median explanation: You put the numbers in order and the middle number is the median.

Interquartile range explanation: The 2 numbers above and below the median are Q1 and Q3, you subtract those and get your interquartile range.

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What is the answer to 5x=3x-8

miv72 [106K]

Answer:

x=-4

Step-by-step explanation:

5x=3x-8 you subtract 3x from both sides.

2x=-8 then you divide by the number next to the x. meaning 2

x=-4

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3 years ago

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WHAT IS THE ANSWER TO y= 4x + 11 pls. Hurry!!!! :)

lesya [120]

Slope is 4

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3 years ago

Mr. george spent 1,008 on a couch. he wpent 1,860 more on a plasma tv than he did on the couch. how much did mr. george spend on

lora16 [44]

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3 years ago

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The number of typographical errors on a page of the first booklet is a Poisson random variable with mean 0.2. The number of typo

muminat

Answer:

The required probability is 0.55404.

Step-by-step explanation:

Consider the provided information.

The number of typographical errors on a page of the first booklet is a Poisson random variable with mean 0.2. The number of typographical errors on a page of second booklet is a Poisson random variable with mean 0.3.

Average error for 7 pages booklet and 5 pages booklet series is:

λ = 0.2×7 + 0.3×5 = 2.9

According to Poisson distribution: $P(k{\text{ events in interval}})={\frac {\lambda ^{k}e^{-\lambda }}{k!}}$

Where $\lambda$ is average number of events.

The probability of more than 2 typographical errors in the two booklets in total is:

$P(k > 2)= 1 - {P(k = 0) + P(k = 1) + P(k = 2)}$

Substitute the respective values in the above formula.

$P(k > 2)= 1 - ({\frac {2.9 ^{0}e^{-2.9}}{0!}} + \frac {2.9 ^{1}e^{-2.9}}{1!}} + \frac {2.9 ^{2}e^{-2.9}}{2!}})$

$P(k > 2)= 1 - (0.44596)$

$P(k > 2)=0.55404$

Hence, the required probability is 0.55404.

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3 years ago

Output<br>4<br>7<br>12<br>rule: X-5

makvit [3.9K]

Answer:

-1

Step-by-step explanation:

4 - 5 = -1

7 - 5 = 2

12 - 5 = 7

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3 years ago