Answer:


Step-by-step explanation:
We are given the following information in the question:
Mean, μ = 500
Standard Deviation, σ = 100
We are given that the distribution of SAT score is a bell shaped distribution that is a normal distribution.
Formula:

We have to find the value of x such that the probability is 0.64
P(X<x) = 0.64
Calculation the value from standard normal z table, we have, 


Answer:
816 cm²
Step-by-step explanation:
Surface area of the composite figure = (surface area of the larger rectangular prism + surface area of the smaller rectangular prism) - area of the side of the smaller rectangular prism that is joined to the bigger prism.
✔️Surface area of the larger rectangular prism:
Area = L*W*H = 20*5*6 = 600 cm²
✔️surface area of the smaller rectangular prism:
Area = L*W*H = 12*4*6 = 288 cm²
✔️area of the side of the smaller rectangular prism that is joined to the bigger prism.
Area = L*W = 12*6 = 72 cm²
Surface area of the composite = (600 + 288) - 72 = 888 - 72 = 816 cm².
Answer: (a) P(no A) = 0.935
(b) P(A and B and C) = 0.0005
(c) P(D or F) = 0.379
(d) P(A or B) = 0.31
Step-by-step explanation: <u>Pareto</u> <u>Chart</u> demonstrates a relationship between two quantities, in a way that a relative change in one results in a change in the other.
The Pareto chart below shows the number of people and which category they qualified each public school.
(a) The probability of a person not giving an A is the difference between total probability (1) and probability of giving an A:
P(no A) = 
P(no A) = 1 - 0.065
P(no A) = 0.935
b) Probability of a grade better than D, is the product of the probabilities of an A, an B and an C:
P(A and B and C) = 
P(A and B and C) = 
P(A and B and C) = 0.0005
c) Probability of an D or an F is the sum of probabilities of an D and of an F:
P(D or F) = 
P(D or F) = 
P(D or F) = 0.379
d) Probability of an A or B is also the sum of probabilities of an A and of an B:
P(A or B) = 
P(A or B) = 
P(A or B) = 0.31
None. They're already pickled so someone else must've picked them before him.