Answer:
3/7
Step-by-step explanation:
The probability of at least is 1 - the probability of at most
P(at least x) = 1 - P(at most x)
The given is:
1. A bus arrives at a bus stop every 35 minutes
2. You arrive at the bus stop at a random time
3. You will have to wait at least 20 minutes for the bus
∵ The bus arrives at a bus stop every 35 minutes
∵ You arrive at the bus stop at a random time
∵ You will wait at most for 20 minutes for the bus
∴ P(at most 20 minutes) =
∵ P(at least 20 minutes) = 1 - P(at most 20 minutes)
∴ P(at least 20 minutes) = 1 -
∴ P(at least 20 minutes) =
- Simplify the fraction by divide up and down by 5 and you will get your answer!
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Answer:
12
Step-by-step explanation:
3 x 4
3 is how far the shape goes to the left.
4 is how far it goes to the bottom
you multiply the two numbers to cover the area
Answer:

Step-by-step explanation:





Let <em>a</em> and <em>b</em> be the two numbers. Then
<em>a</em> + <em>b</em> = -4
<em>a b</em> = -2
Solve the second equation for <em>b</em> :
<em>b</em> = -2/<em>a</em>
Substitute this into the first equation:
<em>a</em> - 2/<em>a</em> = -4
Multiply both sides by <em>a</em> :
<em>a</em>² - 2 = -4<em>a</em>
Move 4<em>a</em> to the left side:
<em>a</em>² + 4<em>a</em> - 2 = 0
Use the quadratic formula to solve for <em>a</em> :
<em>a</em> = (-4 ± √(4² - 4(-2))) / 2
<em>a</em> = -2 ± √6
If <em>a</em> = -2 + √6, then
-2 + √6 + <em>b</em> = -4
<em>b</em> = -2 - √6
In the other case, we end up with the same numbers, but <em>a</em> and <em>b</em> are swapped.