If A has coordinates (2, –1) and B has coordinates (–1, 1), what are the coordinates of the midpoint of AB¯¯¯¯¯¯ ?
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The value of cos A is √(1 + x²)/ (1 - x²) /√1 + x
<h3>Trigonometric ratios</h3>
It is important to note that
sin A = opposite/ hypotenuse
cos A = adjacent/ hypotenuse
Then,
opposite =
Hypotenuse =
Let's find the adjacent side using the Pythagorean theroem
cos A = x/hypotenuse
cos A = √(1 + x²)/ (1 - x²) /√1 + x
Thus, the value of cos A is √(1 + x²)/ (1 - x²) /√1 + x
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