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Mila [183]
3 years ago
10

To run a mile, Jamal must run 4 laps around the track. His goal is to run 3 miles. Jamal has run 9 laps so far.

Mathematics
2 answers:
vodka [1.7K]3 years ago
7 0
Don’t really know what your question is but 4 laps times 3 miles is 12 laps. He’s got 3 more laps to finish his goal.

Pro tip: Include the actual question
8_murik_8 [283]3 years ago
5 0

Answer:

1 mile = 4 laps

3 miles = 12 laps

9/4 = x /1

9/4 = 2.25

he has run 2.25 miles = 9 laps

he needs to run 0.75 miles = 3 laps

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Divide 5 in a ratio of 1:2:3
anastassius [24]
In plain and short, we simply divide 5 by (1+2+3) and then distribute the pieces likewise

\bf 5\qquad 1:2:3\qquad \cfrac{5}{1+2+3}\implies \cfrac{5}{6}
\\\\\\
\stackrel{\textit{ratio of 1}}{1\left( \frac{5}{6} \right)}\qquad \stackrel{\textit{ratio of 2}}{2\left( \frac{5}{6} \right)}\qquad \stackrel{\textit{ratio of 3}}{3\left( \frac{5}{6} \right)}\qquad \implies \qquad \frac{5}{6}~:~\frac{5}{3}~:~\frac{5}{2}

add the ratios up, and you'll get 5.
4 0
3 years ago
PLEASE HELP! THANKS!!
stepladder [879]
X=12 because I said so and I’m smart
7 0
3 years ago
If g(x) is the inverse of f(x) and f(x) = 4x+12, what is g(x)?
KatRina [158]
Your answer to the question would be g(x)=4x-3
8 0
3 years ago
Find the equation of the line passing through the points (6,3) and (-4,3)<br> Y=
Molodets [167]

{ \qquad\qquad\huge\underline{{\sf Answer}}}

Equation of line passing through given points :

Let's proceed with two point form ~

\qquad \sf  \dashrightarrow \: y - y1 =  \cfrac{y2 - y1}{x2 - x1} (x - x1)

Assume :

\qquad \sf  \dashrightarrow \: y - 3=  \cfrac{3 - 3}{ - 4 - 6} (x - 6)

\qquad \sf  \dashrightarrow \: y - 3=  \cfrac{0}{ - 10} (x - 6)

\qquad \sf  \dashrightarrow \: y - 3 = 0

\qquad \sf  \dashrightarrow \: y = 3

So, the equation of required line is : y = 3 ~

5 0
1 year ago
Four cards are dealt from a standard fifty-two-card poker deck. What is the probability that all four are aces given that at lea
elena-s [515]

Answer:

The probability is 0.0052

Step-by-step explanation:

Let's call A the event that the four cards are aces, B the event that at least three are aces. So, the probability P(A/B) that all four are aces given that at least three are aces is calculated as:

P(A/B) =  P(A∩B)/P(B)

The probability P(B) that at least three are aces is the sum of the following probabilities:

  • The four card are aces: This is one hand from the 270,725 differents sets of four cards, so the probability is 1/270,725
  • There are exactly 3 aces: we need to calculated how many hands have exactly 3 aces, so we are going to calculate de number of combinations or ways in which we can select k elements from a group of n elements. This can be calculated as:

nCk=\frac{n!}{k!(n-k)!}

So, the number of ways to select exactly 3 aces is:

4C3*48C1=\frac{4!}{3!(4-3)!}*\frac{48!}{1!(48-1)!}=192

Because we are going to select 3 aces from the 4 in the poker deck and we are going to select 1 card from the 48 that aren't aces. So the probability in this case is 192/270,725

Then, the probability P(B) that at least three are aces is:

P(B)=\frac{1}{270,725} +\frac{192}{270,725} =\frac{193}{270,725}

On the other hand the probability P(A∩B) that the four cards are aces and at least three are aces is equal to the probability that the four card are aces, so:

P(A∩B) = 1/270,725

Finally, the probability P(A/B) that all four are aces given that at least three are aces is:

P=\frac{1/270,725}{193/270,725} =\frac{1}{193}=0.0052

5 0
3 years ago
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