Just subisute values that will work
one easy way is to make one sides equal to only one of the placeholders, like y, and then lug in values in for x exg
x+2y=3
subtract x from both sides
2y=3-x
divideb bith sides by 2
y=-1/2x+3
subsitute valudes for x and get values for y
if x=2 then
y=-1/2(2)+3
y==-1+3
y=2
when x=2, y=2
when y=0 then y=3
The definition of a rhombus is that it's a polygon with four congruent sides. If you split one into two pieces with a diagonal, then yes, it will be two isosceles triangles because two sides are congruent.
Q1 :
x + (x+25) = 131
2x + 25 = 131
2x = 131-25
2x = 106
x = 53
53+25 = 78
Therefore, 53+78=131
Q2 :
x + (x+14) = 58
2x + 14 = 58
2x = 58-14
2x = 44
x = 22
22+14 = 36
Therefore, 22+36=58
Q3 :
let ‘b’ be basketball
b + (3+b) = 27
2b + 3 = 27
2b = 27-3
2b = 24
b = 12
12 + 3 = 15
Therefore, 12 + 15 = 27
12 basketballs and 15 footballs were sold on Saturday
Q4 :
let ‘s’ be soup
s + 2s = 738
3s = 738
s = 246
246 x 2 = 492
Therefore, the hamburger has 492 calories while the soup as 246 calories
hope it helps somehow!
Given:
uniforms in a package of 8.
127 people with 3 uniforms each.
127 x 3 = 381 uniforms
381 ÷ 8 = 47.625 ⇒ 48 packages
The store will need to order 48 packages of uniforms to fulfill the uniform requirement of 127 people. There will also be 3 uniforms left in excess of the 48 packages.
48 * 8 = 384
384 - 381 = 3 excess uniform
2 is the only right answer. If it has right/left symmetry, then f(-x) = f(x), meaning it's even.
extra info: 3 and 4 are the same thing
5 works for odd functions (like sin(x))
