Question

Find the ordered pairs. {Y=(x+2)^2+1 {Y=x+1

Answer 1

Answer:

$\large \boxed{\sf \bf \ \ \text{No solution in }\mathbb{R} \ \ }$

Step-by-step explanation:

Hello, please consider the following.

We can say that y = y, right? So it gives.

$(x+2)^2+1=x+1\\\\\text{*** We develop the left side. ***}\\\\x^2+2\cdot 2\cdot x + 2^2+1=x+1\\\\\text{*** We subtract x+1. ***}\\\\x^2+4x+5-x-1=0\\\\x^2+3x+4=0$

$\Delta=b^2-4ac = 3^2-4*4=9-16=-7$

The Delta is negative so there is no solution.

Hope this helps.

Do not hesitate if you need further explanation.

Thank you