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vivado [14]
3 years ago
14

Ming has a standard 52-card deck. A standard 52-card deck has 4 suits (♠, ♣,♦, and ♥) and an equal number of cards of each suit.

She is going to randomly draw a card from the deck 300 times, putting the card back in the deck after each draw.
Complete the following statement with the best prediction.
Ming will draw something other than a ♥…
Please choose from one of the following options.

A.)Exactly 150 times
B.)Close to 150 times but probably not exactly 150 times
C.)Exactly 225 times
D.)Close to 225 times but probably not exactly 225 times
Mathematics
1 answer:
soldier1979 [14.2K]3 years ago
3 0

Answer:

Option D.

Step-by-step explanation:

Total number of cards = 52

Total number of cards of each suit (♠, ♣,♦, and ♥) = 13

The probability of getting a card of heart is

\text{Probability of getting a card of heart}=\frac{\text{Number of heart cards}}{\text{Total number of cards}}

\text{Probability of getting a card of heart}=\frac{13}{52}

\text{Probability of getting a card of heart}=\frac{1}{4}

The probability of getting a card other then heart is

1-\frac{1}{4}=\frac{3}{4}

If Ming randomly draw a card from the deck 300 times, putting the card back in the deck after each draw, then the number of cards she will draw something other than a heart is

300\times \frac{3}{4}=225

Close to 225 times but probably not exactly 225 times.

Therefore, the correct option is D.

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Answer:

This proves that f is continous at x=5.

Step-by-step explanation:

Taking f(x) = 3x-1 and \varepsilon>0, we want to find a \delta such that |f(x)-14|

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Suppose m is in the line given by the equation 6x-3y=7, and suppose n is the line perpendicular to m and passing Nd through the
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Answer:

The x co-ordinate o intersection of line k and n is \frac{8}{11}

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Given as :

The equation of line m is 6 x - 3 y = 7

So, in the standard form , line equation is

y = a x + c  , where a is the slope

So,  6 x - 3 y = 7 can be written as

3 y = 6 x - 7

or,  y = 2 x - \frac{7}{3}       ........1

So, slope of this line = a = 2

Now, The line n is perpendicular to line m and passing through line ( 6 , 2 )

So, Slope of line n = b

For , perpendicular lines , products of slope = - 1

Or, a × b = -1

∴  b = - \frac{1}{a}

I.e b = - \frac{1}{2}

So,equation of line n with slope b and passing through line ( 6 , 2 ) is

y - y_1 = b ( x - x_1 )

or, y - 2 =  - \frac{1}{2} ( x - 6 )

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or, 2 y - 4 = - x + 6

or, x + 2 y -10 = 0          ........2

Again, equation of line k with slope 5 and y intercept = 1

For y intercept , x coordinate = 0

y = c x + c

or, 1 = c× ( 0 ) + c

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Or, equation of line k is

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Now intersection of line k and n is

put the value of y from eq 3 into eq 2

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or, 11 x - 8 = 0

or 11 x = 8

∴  x = \frac{8}{11}

Hence The x co-ordinate o intersection of line k and n is \frac{8}{11}  Answer

4 0
3 years ago
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