Answer:
You need to find the surface of each area and sum them up.
Step-by-step explanation:
You will need the surface area for each side.
So 2 up-bottom, 2 left-right and two front-back
2*(4*3) + 2*(2*4) + 2(3*2)
2*12 + 2*8 + 2*6
24 + 16 + 12
Total area = 52
Answer:
No Solution
Step-by-step explanation:
all the ordered pair doesn't satisfy the equation.
You have to plug in the numbers for x and then solve.
For example, when it says y=2x-4, you put -2 and the numbers below it for x and then solve.
(I don't want to give you the answer to everything and want to help you understand how to do it.)
Answer:
- 
Step-by-step explanation:
Given:
10 poker chips:
Let the stack has positions (1,2,3,4,5,6,7,8,9,10)
So we can find all possible outcomes of the stack is: =
and the possibility of a stack to be identical while flipping is:
So the different 10-chip stacks can Dave make if two stacks are not considered distinct:
-
Answer:
see below
Step-by-step explanation:
6y = 12x + 26
15y = 45x + 60
First let's simplify these equations.
6y = 12x + 26
Divide each term by 6.
y = 2x + 26/6
Simplify the fraction.
26/6
= 13/3
Your simplified equation is:
y = 2x + 13/3
Let's simplify the other equation.
15y = 45x + 60
Divide each term by 15.
y = 3x + 4
These are your simplified equations.
y = 2x + 13/3
y = 3x + 4
We can see that the slope of the first equation is not equal to the slope of the second equation.
- equation 1: slope is 2 shown from 2x
- equation 2: slope is 3 shown from 3x
The y-intercept of the first equation is not equal to the y-intercept of the second equation.
- equation 1: y-intercept is 13/3 shown by + 13/3
- equation 2: y -intercept is 4 shown by + 4
Now we want to solve the equations.
Both equations are equal to y, so you can set them equal to each other.
2x + 13/3 = 3x + 4
Combine like terms.
1/3 = x
Plug x = 1/3 into both of the equations separately..
y = 2(1/3) + 13/3
y = 2/3 + 13/3
y = 15/3
y = 5
y = 3(1/3) + 4
y = 3/3 + 4
y = 1 + 4
y = 5
Your solution is (1/3, 5)
The system of equations has one solution.
Hope this helps!
