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ra1l [238]
3 years ago
10

Velocity calculation

Biology
1 answer:
svetoff [14.1K]3 years ago
4 0
Answer choice: [C]:
_________________________________________

V = d / t  = 1800 mi / 40 min = 180 mi / 40 min = 45 mi / min .

Which very well could be "Answer choice: [C]:  45 m/min" ; except, this answer choice may have been written incorrectly—and should read:
                                                 "45 m/min."
________________________________________________________

Now, notice that all the answer choices given are in "meters" per (unit time—seconds or mins.

So, we need to convert:

45 mi.  to "meters", or "m".
______________________________________
Note the following conversions:
_______________________________________
 1 mi. = 1750 yd
______________________________________
3 ft. = 1 yd.
____________________________________

1 m = 3.2 ft.
_____________________

So, 1 mi. = ? m ;
_____________________
 1 mi * ( 1760 yd/ mi) * (3 ft / 1 yd) * ( 1m / 3.2 ft) = _?_  m ?
_____________________________________________________
On the "left hand side" , the units of  "mi", "yd", and "ft" ; cancel to "1" ;
  ____________________________________________________
    and we are left with:
______________________________________
[(1760 * 3)]  /  [(3)*(3.2)]   m  = (5280 / 9.6) m  =  550 m .
______________________________________________
So, we have:  550 m / min ; which match NONE of the answer choices.

However, it is possible that choices A or B, which are given in "m/sec" (meters per second); are among the correct choices.
____________________________________________

So, we convert:   550 m / min to:   "m / sec " ;
______________________________________
( 550 m/ min)*(1 min/ 60 sec) =  (550/60) m/sec = (55/6) m/ sec
                                                                                    = 9 1/6 m / sec .
_____________________________________________________
                                                                 which is:  None of the above.
______________________________________________________
                     Unless the answer choices were written incorrectly.




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Answer:

All of the above answer choices are correct.

Explanation:

Test cross is done to find out the genotype of an individual displaying dominant phenotype as it can be homozygous or heterozygous. To find this the individual is crossed with a recessive phenotype individual. For example: a dominant trait tall height can be homozygous TT or heterozygous Tt. If it is TT all the offspring of test cross with tt will be tall. If it is Tt half of the offspring will be tall and half of the offspring will be short.

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