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Serga [27]
2 years ago
12

Many coastal communities oppose the proposal to set up tidal plants, even though they recognize that the solution to the current

energy crisis could be tidal power. Which of these statements best describes the possible impact of using tidal power on these communities?
It may generate waste.

It may cause alteration of tides.

It may generate harmful emissions. (Not this)

It may take up recreational space.
Biology
1 answer:
Leni [432]2 years ago
4 0

Answer:

Knowing others is intelligence; knowing yourself is true wisdom. mastering others is strength; mastering yourself is true power. if you realize that you have enough, you are truly rich, "And the cause of not following your heart, is in spending the rest of your life wishing you had."

Explanation:

I need points so SORRY!

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On May 18, 1980, Mount St. Helens in Washington State experienced a huge volcanic eruption after a magnitude 5.1 earthquake. Dur
Artyom0805 [142]

Answer:

primary succession

Explanation:

Primary succession starts in regions where there is no soil or where the soil is incapable of sustaining life due to any recent lava flows or newly formed sand dunes. Primary succession may lead to the formation of islands on land formed from glacial retreats or on new volcanic rock.

Primary succession occurred in the ecosystem around Mount St. Helens after the volcano erupted.

6 0
3 years ago
CPT codes for diagnostic radiology for the hemic and lymphatic systems are covered under which range?a. 75600-75989b. 77001-7702
Ket [755]

Answer:

a. 75600-75989

Explanation:

CPT(current procedural terminologies)are a set of medical codes used to describe procedures and services perform by health practitioners.

Hemic and lymphatic systems covers procedures of the spleen bone marrow and stem cells and the lymph nodes.

Here codes for procedures such as Splenectomy can be found.

They will be covered under the range 75600-75989 of the cpt codes.

3 0
3 years ago
If a whitefish blastula begins as a single cell, how many mitotic divisions will it take to generate 16 cells?
Natali5045456 [20]

The answer is C. This is because, with every mitotic division, the cell population doubles because each cell gives rise to two daughter cells. Therefore, mathematically, after 4 division of one cell, there will end up with 16 cells (2^4).   

4 0
3 years ago
PLEASE HELP ASAP
il63 [147K]
I took this quiz the answer is C, protiens
8 0
3 years ago
The CRISPR/Cas9 system can cleave genomic DNA at sequences other than the desired target, a phenomenon referred to as off target
Deffense [45]

Answer:

The minimum length of a sgRNA sequence to avoid off target cleavage by the CRISPR/Cas system in the fly fruit genome is 14 bases

Explanation:

We are trying to use the CRISPR/Cas system to cleavage the genome of the fruit fly (which is 1.4x10^8 bp long). Also we desire the cleavage to be unique. That means we need a target sequence long enough to be able to assume it will only appear once in the genome.

First, we should think that in every position, we can find one out of four different nucleotide (A, C, T, G). So, the probability of getting a sequence of a given length "n" will be (1/4)^n (We are assuming that the probability of finding a nucleotide in the position "i", it's independent of the nucleotide we find in any other position "j").

Also, to know how many times a sequence will appear in a genome (the expected value of occurrence), we must multiply the probability of that sequence to randomly occur by the length of the genome. For our specific example, the number of occurence of a sequence of length "n" is:

nºoccurence=[(1/4)^n]*1.4*10^8

But in this case, what we want is the expected number of times the sequence will appear to be 1, and we want to obtain the length of the target sequence (n).

Given the information above, we know that:

[(1/4)^n]*1.4*10^8 =1

[(1/4)^n]=(1/1.4*10^8)=1.4*10^-8

Then, if we want to calculate n, we can use logarithms and its properties to get:

log[(1/4)^n]=log[1.4*10^-8]

n*log[(1/4)]=log[1.4*10^-8]

n=log[1.4*10^-8]/log[(1/4)] => n=13.29 approximately.

As the sequence needs to have a natural number of elements, <u>we can conclude that using a target sequence of a minimum of 14 bases with the CRISPR/Cas system in the fly fruit genome should be enough to avoid off target cleavage.</u>

3 0
3 years ago
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