Question

a right triangle has side lengths 8 15 and 17 as shown below use these lengths to find tan B sin B and cosine B​

Answer 1

Answer:

sin(B) =  $\frac{15}{17}$

cos(B) = $\frac{8}{17}$

tan(B) = $\frac{15}{8}$

Step-by-step explanation:

I always find it easiest to model out the triangle: Angle B will be at the converging point of a and c.

Using SOH CAH TOA, we know that the Sin of an angle will be its opposite over hypotenuse. The opposite is 15, and the hypotenuse is 17.

So  $\frac{15}{17}$ is the sin of B.

We also know that the cosine of B will be it's adjacent over hypotenuse. The adjacent is 8 and the hypotenuse is 17, so

$\frac{8}{17}$

Lastly, we know the tangent of B will be it's opposite over adjacent. The opposite of B is 15, and it's adjacent is 8, so

$\frac{15}{8}$ is the tangent of B.

Hope this helped!