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2 years ago

Perform the operation. (3x^2+4)-(-5x^2+4x-1)

Mathematics

1 answer:

Galina-37 [17]2 years ago

7 0

Answer:

8x^2-4x+5

Step-by-step explanation:

(3x^2+4)-(-5x^2+4x-1)

Let's start by removing the parentheses.

3x^2+4-(-5x^2)-4x+1

Now let's reorder the equation to make it easier to combine like terms.

3x^2+5x^2-4x+1+4

Combine like terms.

8x^2-4x+5

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Solve the following inequality 10>2x+5

Alisiya [41]

Answer: 2.5 is greater than x

Step-by-step explanation:

7 0

3 years ago

Match solutions and differential equations. Note: Each equation may have more than one solution. Select all that apply. (a) 7y''

Nonamiya [84]

Answer:

a- $e^x,e^{-x}$

b- $x^{-2}$

c- $x^3$

Step-by-step explanation:

a.7 y''-7 y =0

Auxillary equation

$D^2-1=0$

$(D-1)(D+1)=0$

D=1,-1

Then , the solution of given differential equation

$y=e^x,y=e^{-x}$

2. $7x^2y''+14xy'-14 y=0$

Y= $y=x^3$

$y=3x^2$

$y''=6x$

Substitute in the given differential equation

$42x^3+42x^3-14x^3\neq 0$

Hence, $x^3$ is not a solution of given differential equation

$e^x,e^{-x}$ are also not a solution of given differential equation.

y= $x^{-2}$

$y'=-2x^{-3}$

$y''=6x^{-4}$

Substitute the values in the differential equation

$7x^2(6x^{-4})+14x(-2x^{-3})-14 x^{-2}$

= $42x^{-2}-28x^{-2}-14x^{-2}=0$

Hence, $x^{-2}$ is a solution of given differential equation.

c. $7x^2y''-42y=0$

$y=x^3$

$y'=3x^2$

$y''=6x$

Substitute the values in the differential equation

$42x^3-42x^3=0$

Hence, $x^3$ is a solution of given differential equation.

a- $e^x,e^{-x}$

b- $x^{-2}$

c- $x^3$

6 0

3 years ago

Read 2 more answers

According to the empirical rule, if the data form a "bell-shaped curve" (normal distribution), approximately what percent of the

Ann [662]

Answer: B. 95.0

Step-by-step explanation:

In statistics , the famous empirical rule says that " if the data is normally distributed then 68% of the observations will be contained within $\pm1$ standard deviations from the arithmetic mean, 95% of the observations will be contained within $\pm2$ standard deviations from the arithmetic mean and 99.7% of the observations will be contained within $\pm3$ standard deviations from the arithmetic mean".