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Ivahew [28]
3 years ago
5

SOMEONE PLEASE HELP ME! I have a few of the explanations but I'm not sure if I need more please suggest some thank you

Mathematics
1 answer:
lesantik [10]3 years ago
5 0

Answer:

For tingle #1

We can find angle C using the triangle sum theorem: the three interior angles of any triangle add up to 180 degrees. Since we know the measures of angles A and B, we can find C.

C=180-(A+B)

C=180-(21.24+27.14)

C=131.62

We cannot find any of the sides. Since there is noting to show us size, there is simply just not enough information; we need at least one side to use the rule of sines and find the other ones. Also, since there is nothing showing us size, each side can have more than one value.  

For triangle #2

In this one, we can find everything and there is one one value for each.

- We can find side c

Since we have a right triangle, we can find side c using the Pythagorean theorem

b^2=a^2+c^2

4^2=2^2+c^2

16=4+c^2

12=c^2

c=\sqrt{12}

c=2\sqrt{3}

- We can find angle C using the cosine trig identity

cos(C)=\frac{adjacent}{hypotenuse}

cos(C)=\frac{2}{4}

C=arccos(\frac{2}{4} )

C=60

- Now we can find angle A using the triangle sum theorem

A=180-(B+C)

A=180-(90+60)

A=30

For triangle #3

Again, we can find everything and there is one one value for each.

- We can find angle A using the triangle sum theorem

A=180-(B+C)

A=180-(90+34.88)

A=55.12

- We can find side a using the tangent trig identity

tan(C)=\frac{opposite-side}{adjacent-side}

tan(34.88)=\frac{7}{a}

a=\frac{7}{tan(34.88)}

a=10.04

- Now we can find side b using the Pythagorean theorem

b^2=a^2+c^2

b^2=10.04^2+7^2

b^2=149.8

b=\sqrt{149.8}

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2x+3y=1 and y=-2 - 9 solve using linear combination method. Please explain steps.
kaheart [24]

Answer:

x=17

Step-by-step explanation:

2x+3y=1

y=-2-9

  • In order to combine these two equations, an idea you need to keep in mind is finding a way of setting these equations as equal to each other. I saw that each equation shared a common value, y. In this case, we need to isolate y in the first equation so that both equations =y.

2x+3y=1

3y=-2x+1

\frac{3y}{3}=\frac{-2x+1}{3}

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  • With this, we now know that both -2-9 and -\frac{2}{3}x+\frac{1}{3} are equal to y, so we can set them equal to each other.

y=-\frac{2}{3}x+\frac{1}{3}

y=-11

-\frac{2}{3}x+\frac{1}{3}=-11

  • Reply to this if anything I'm saying or doing is confusing in any way, or if you find a mistake. :) Solve for x.

-\frac{2}{3}x+\frac{1}{3}=-11

-\frac{2}{3}x=-11-\frac{1}{3}

-\frac{2}{3}x =-\frac{33}{3}-\frac{1}{3}

-\frac{2}{3}x =-\frac{34}{3}

-\frac{2}{3}x(-\frac{3}{2})=-\frac{34}{3}(-\frac{3}{2})

x=\frac{102}{6}=17

x=17

  • Hopefully this answer is correct AND makes sense in terms of how I achieved it. Again, reply to this with any questions or mistakes I made and I'll do my best to answer or fix them.

 

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Step-by-step explanation:

<u>Given </u>

  • a = 11x

<u>Perimeter of a square is:</u>

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<u>Substitute the value:</u>

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