A hubcap has a radius of 14 centimeters. What is the area of the hubcap?asap pls

Mathematics

1 answer:

Mashutka [201]3 years ago

8 0

Answer:

The area of the hubcap is 196π or 615.7521601

Step-by-step explanation:

You can use A=πr² to find the area of a circle. So that would mean that A equals 14². 14²=196. If the answer is in π form, then the answer is 196π. If not then its 196·π. 196·π=615.7521601

Hope that helps!

You might be interested in

Graph the function y = |1.6x – 2| – 3.2. Over which interval is the function increasing?

klasskru [66]

You are to graph y = |1.6x – 2| – 3.2. I trust you know that the graph of y=|x| is v-shaped, opening up, with vertex at (0,0).

Let's rewrite y = |1.6x – 2| – 3.2 by factoring 1.6 out of |1.6x - 2|:

y = 1.6*|x – 2/1.6| – 3.2

This tells us that the vertex of y = |1.6x – 2| – 3.2 is at (2/1.6, -3.2). If you need an explanation of why this is, please ask.

Plot the vertex at (1.25, -3.2).
Find the y-intercept: Let x = 0 in y = |1.6x – 2| – 3.2 and find y:

y = 2-3.2 = -1.2

The y-intercept is located at 0, -1.2)

Plot this y-intercept.

Now draw a straight line from the vertex to this y-intercept. Reflect that line across the y-axis to obtain the other half of the graph.

8 0

2 years ago

Read 2 more answers

How many cups does a gallon equals

kolbaska11 [484]

Answer:

Step-by-step explanation:

There are 16 cups in a gallon

5 0

2 years ago

Read 2 more answers

to build the garden of your dreams you need 11 m^3 of coil containing 46% clay. you have two types of soil you can combine to ac

aivan3 [116]

Answer: 9m^3 of soil with 50% clay and 2m^3 of soil with 28% clay is required

Step-by-step explanation:

Let x represent the quantity of the soil containing 50% clay that you would use.

Let y represent the quantity of the soil containing 28% clay that you would use.

To build the garden of your dreams you need 11 m^3 of soil.

x + y = 11 - - - - - - - - -1

Since the soil must contain 46% clay, the total amount of clay required is 46/100 × 11 = 5.06 m^3.

you have two types of soil you can combine to achieve this: soil with 50% clay and soil with 28% clay. This means that the quantity of both soils required to achieve 5.06 m^3 will be

0.5x + 0.28y = 5.06 - - - - - - - -2

Substituting x = 11 - y into equation 1, it becomes

0.5(11 - y) + 0.28y = 5.06

5.5 - 0.5y + 0.28y = 5.06

- 0.5y + 0.28y = 5.06 - 5.5

- 0.22y = - 0.44

y = - 0.44/ -0.22 = 2

Substituting y = 2 into x = 11 - y, it becomes

x = 11 - 2 = 9

7 0

3 years ago

Can u help me please better picture

gladu [14]

Hi, there.

For this question, we can apply the Pythagorean theorem $a^2 + b^2 = c^2$ .

I'm sure you've seen this equation before, and they kind of tried to trip you up with this problem. Trust me, it's easier than it looks. Let's break it down.

Lengths a and b both have the value of 48, which means that the value s in $\sqrt{2s^2}$ is 48, because the length of the hypotenuse is the same as the length and height squared multiplied by 2.