Question 1:
--------------------------------------------------------------------
Find Slope
--------------------------------------------------------------------
Equation: y = 5x - 2
Slope = 5
Slope of parallel line = 5
--------------------------------------------------------------------
Insert slope into the general equation y = mx + c
--------------------------------------------------------------------
y = 5x + c
--------------------------------------------------------------------
Find y-intercept
--------------------------------------------------------------------
At point (2, -1)
y = 5x + c
-1 = 5(2) + c
c = -1 - 10
c = -11
--------------------------------------------------------------------
Insert y-intercept into the equation
--------------------------------------------------------------------
y = 5x + c
y = 5x - 11
--------------------------------------------------------------------
Answer: y = 5x - 11
--------------------------------------------------------------------
Question 2:
--------------------------------------------------------------------
Find Slope
--------------------------------------------------------------------
y = 9x
Slope = 9
Slope of the parallel line = 9
--------------------------------------------------------------------
Insert slope into the equation y = mx + c
--------------------------------------------------------------------
y = 9x + c
--------------------------------------------------------------------
Find y-intercept
--------------------------------------------------------------------
y = 9x + c
At point (0, 5)
5 = 9(0) + c
c = 5
--------------------------------------------------------------------
Insert y-intercept into the equation
--------------------------------------------------------------------
y = 9x + c
y = 9x + 5
--------------------------------------------------------------------
Answer: y = 9x + 5
--------------------------------------------------------------------
Answer:
3x>12 2x/3 ≤ 6
3x>12, x = 4 2x/3, x = 2 ≤ 6
3x - 2y = 7
-2y = -3x + 7
y = 3/2x - 7/2....slope of this line is 3/2. A perpendicular line will have a negative reciprocal slope. All that means is " flip " the slope and change the sign. So the slope we need is -2/3 (see how I flipped the slope and changed the sign)
y = mx + b
slope(m) = -2/3
(-3,-2).....x = -3 and y = -2
now we sub and find b, the y int
-2 = -2/3(-3) = b
-2 = 2 + b
-2 - 2 = b
-4 = b
so ur perpendicular equation is : y = -2/3x - 4 <==
The answer to this is question is gonna be True!
Answer:
slope=3
Step-by-step explanation:
