1) Volume = L × W × H = 8 × 3 × 5 = <u>120 m³</u>
2) Volume = s³ = 17³ = 17 × 17 × 17 = <u>4913 cm³</u>
3) Volume = s³ = 30³ = 30 × 30 × 30 = <u>27000 cm³</u>
4) Volume = L × W × H = 13 × 5 × 7 = <u>455 cm³</u>
5) Volume = s³ = 15³ = 15 × 15 × 15 = <u>3375 cm³</u>
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Formula's applied:
(a) Volume of rectangle: Length × Width × Height
(b) Volume of Cube: (side)³
Answer:
Option D. (x + 4)(x + 1)
Step-by-step explanation:
From the question given above, the following data were obtained:
C = (6x + 2) L
D = (3x² + 6x + 9) L
Also, we were told that half of container C is full and one third of container D is full. Thus the volume of liquid in each container can be obtained as follow:
Volume in C = ½C
Volume in C = ½(6x + 2)
Volume in C = (3x + 1) L
Volume in D = ⅓D
Volume in D = ⅓(3x² + 6x + 9)
Volume in D = (x² + 2x + 3) L
Finally, we shall determine the total volume of liquid in the two containers. This can be obtained as follow:
Volume in C = (3x + 1) L
Volume in D = (x² + 2x + 3) L
Total volume =?
Total volume = Volume in C + Volume in D
Total volume = (3x + 1) + (x² + 2x + 3)
= 3x + 1 + x² + 2x + 3
= x² + 5x + 4
Factorise
x² + 5x + 4
x² + x + 4x + 4
x(x + 1) + 4(x + 1)
(x + 4)(x + 1)
Thus, the total volume of liquid in the two containers is (x + 4)(x + 1) L.
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