Question

} } -1 " alt=" \sqrt[5]{32^x -1 } } -1 " align="absmiddle" class="latex-formula"> = 0 This Please i don't know how to proceed

Answer 1

Add 1 to both sides
$\sqrt[5]{32^x-1}=1$
raise each side to the 5th power
$32^x-1=1$
add 1 to both sides
$32^x=2$
we can try to match bases
because if, xᵃ=xᵇ where x=x, then a=b
we know that 32=2⁵
and $(x^m)^n=x^{mn}$ so
$32^x=2$ is the same as
$(2^5)^x=2$ or $2^{5x}=2^1$
therefor
5x=1
divide both sides by 5
x=1/5