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2 years ago

Which of the following best describes the relationship between (x-3) and the polynomial x^3+4x^2+2?

Mathematics

2 answers:

Vlada [557]2 years ago

8 0

Answer:

B. (x-3) is not a factor.

Step-by-step explanation:

Anna71 [15]2 years ago

7 0

This is the concept of polynomials, to get the relationship between the (x-3) and (x^3+4x^2+2) we shall proceed as follows;
we first test if (x-3) is a polynomial;
x-3=0
thus;
x=3
substituting the value of x in the polynomial we get:
(3)^3+4(3)^2+2
=65
since the result is not equal to 0, we conclude that there is no relationship between (x-3) and the polynomial. The answer is B. (X-3) is not a factor

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If g(x) is the inverse of f(x) and f(x) = 4x+12, what is g(x)?

KatRina [158]

Your answer to the question would be g(x)=4x-3

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3 years ago

find the values of the six trigonometric functions for angle theta in standard position if a point with the coordinates (1, -8)

frutty [35]

Answer:

cosФ = $\frac{1}{\sqrt{65}}$ , sinФ = $-\frac{8}{\sqrt{65}}$ , tanФ = -8, secФ = $\sqrt{65}$ , cscФ = $-\frac{\sqrt{65}}{8}$ , cotФ = $-\frac{1}{8}$

Step-by-step explanation:

If a point (x, y) lies on the terminal side of angle Ф in standard position, then the six trigonometry functions are:

cosФ = $\frac{x}{r}$
sinФ = $\frac{y}{r}$
tanФ = $\frac{y}{x}$
secФ = $\frac{r}{x}$
cscФ = $\frac{r}{y}$
cotФ = $\frac{x}{y}$

Where r = $\sqrt{x^{2}+y^{2} }$ (the length of the terminal side from the origin to point (x, y)

You should find the quadrant of (x, y) to adjust the sign of each function

∵ Point (1, -8) lies on the terminal side of angle Ф in standard position

∵ x is positive and y is negative

→ That means the point lies on the 4th quadrant

∴ Angle Ф is on the 4th quadrant

∵ In the 4th quadrant cosФ and secФ only have positive values

∴ sinФ, secФ, tanФ, and cotФ have negative values

→ let us find r

∵ r = $\sqrt{x^{2}+y^{2} }$

∵ x = 1 and y = -8

∴ r = $\sqrt{x} \sqrt{(1)^{2}+(-8)^{2}}=\sqrt{1+64}=\sqrt{65}$

→ Use the rules above to find the six trigonometric functions of Ф

∵ cosФ = $\frac{x}{r}$

∴ cosФ = $\frac{1}{\sqrt{65}}$

∵ sinФ = $\frac{y}{r}$

∴ sinФ = $-\frac{8}{\sqrt{65}}$

∵ tanФ = $\frac{y}{x}$

∴ tanФ = $-\frac{8}{1}$ = -8

∵ secФ = $\frac{r}{x}$

∴ secФ = $\frac{\sqrt{65}}{1}$ = $\sqrt{65}$

∵ cscФ = $\frac{r}{y}$

∴ cscФ = $-\frac{\sqrt{65}}{8}$

∵ cotФ = $\frac{x}{y}$

∴ cotФ = $-\frac{1}{8}$

8 0

2 years ago

A farmer want to fence in a rectangular field that encloses 3600 sq feet. The cost 3.50 per foot. Express the total cost c(x) of

Alexeev081 [22]

Answer:

Answers is C (x)=3.50 {x+3600/x} -_-

Step-by-step explanation:

8 0

3 years ago

Which graph represents a line with a slope of and a y-intercept equal to that of the line y = x – 2?

Sindrei [870]

Answer:

(0, -2), (1, -1), (2,0)

Step-by-step explanation:

should be along those lines

8 0

3 years ago

Please help!!

ZanzabumX [31]

The two linear equations in two variable is:

12 x + 3 y = 40

7 x - 4 y = 38

(a) For a system of equations in two Variable

a x + by = c

p x + q y = r

It will have unique solution , when

$\frac{a}{p}\neq \frac{b}{q}\neq\frac{c}{r}$

As, you can see that in the two equation Provided above

$\frac{12}{7}\neq \frac{3}{-4}\neq \frac{40}{38}$

So, we can say the system of equation given here has unique solution.

(b). If point (2.5, -3.4) satisfies both the equations, then it will be solution of the system of equation, otherwise not.

1. 12 x+3 y=40

2. 7 x-4 y=38

Substituting , x= 2.5 , and y= -3.4 in equation (1) and (2),

L.H.S of Equation (1)= 1 2 × 2.5 + 3 × (-3.4)

= 30 -10.20

= 19.80≠ R.H.S that is 40.

Similarly, L H S of equation (2)= 7 × (2.5) - 4 × (-3.4)

= 17.5 +13.6

= 31.1≠R HS that is 38

So, you can Write with 100 % confidence that point (2.5, -3.4) is not a solution of this system of the equation.

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2 years ago