let's bear in mind that an absolute value expression is in effect a piece-wise expression, namely it has a ± versions of the same expression.
![\bf 5|3x-4| = x+1\implies |3x-4|=\cfrac{x+1}{5}\implies \begin{cases} +(3x-4)=\cfrac{x+1}{5}\\[1em] -(3x-4)=\cfrac{x+1}{5} \end{cases} \\\\[-0.35em] ~\dotfill\\\\ +(3x-4)=\cfrac{x+1}{5}\implies 3x-4=\cfrac{x+1}{5}\implies 15x-20=x+1 \\\\\\ 14x-20=1\implies 14x=21\implies x = \cfrac{21}{14}\implies \boxed{x=\cfrac{3}{2}} \\\\[-0.35em] ~\dotfill\\\\ -(3x-4)=\cfrac{x+1}{5}\implies -3x+4=\cfrac{x+1}{5}\implies -15x+20=x+1 \\\\\\ 20=16x+1\implies 19=16x\implies \boxed{\cfrac{19}{16}=x}](https://tex.z-dn.net/?f=%5Cbf%205%7C3x-4%7C%20%3D%20x%2B1%5Cimplies%20%7C3x-4%7C%3D%5Ccfrac%7Bx%2B1%7D%7B5%7D%5Cimplies%20%5Cbegin%7Bcases%7D%20%2B%283x-4%29%3D%5Ccfrac%7Bx%2B1%7D%7B5%7D%5C%5C%5B1em%5D%20-%283x-4%29%3D%5Ccfrac%7Bx%2B1%7D%7B5%7D%20%5Cend%7Bcases%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%2B%283x-4%29%3D%5Ccfrac%7Bx%2B1%7D%7B5%7D%5Cimplies%203x-4%3D%5Ccfrac%7Bx%2B1%7D%7B5%7D%5Cimplies%2015x-20%3Dx%2B1%20%5C%5C%5C%5C%5C%5C%2014x-20%3D1%5Cimplies%2014x%3D21%5Cimplies%20x%20%3D%20%5Ccfrac%7B21%7D%7B14%7D%5Cimplies%20%5Cboxed%7Bx%3D%5Ccfrac%7B3%7D%7B2%7D%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20-%283x-4%29%3D%5Ccfrac%7Bx%2B1%7D%7B5%7D%5Cimplies%20-3x%2B4%3D%5Ccfrac%7Bx%2B1%7D%7B5%7D%5Cimplies%20-15x%2B20%3Dx%2B1%20%5C%5C%5C%5C%5C%5C%2020%3D16x%2B1%5Cimplies%2019%3D16x%5Cimplies%20%5Cboxed%7B%5Ccfrac%7B19%7D%7B16%7D%3Dx%7D)
Answer:
it can't be solved
Step-by-step explanation:
Step-by-step explanation:
Multiply the number outside the brackets to the numbers inside:
So,
9 * 9x = 81x
9 * 2y = 18y
9 x -6 = -54
So the simplified or equivalent expression is:
81x + 18y - 54
Answer: about 16
Step-by-step explanation:
See picture for more information
Answer:
9.) B. division
10.) 8
Explanation:
9. Which operation to do first in order of operations?
Answer: Applying BODMAS where:
[B] brackets
[O] order
[D] division
[M] multiplication
[A] addition
[S] subtraction
Maintaining order, division operation is done first. Then multiplication and then addition and so on.
10. Given that N = 48 ÷ 3 × 2
⇒ N = 48 ÷ 3 × 2
⇒ N = 48 ÷ 6
⇒ N = 8
