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Komok [63]
3 years ago
6

Suppose you are climbing a hill whose shape is given by the equation z = 1300 − 0.005x2 − 0.01y2, where x, y, and z are measured

in meters, and you are standing at a point with coordinates (100, 120, 1106). The positive x-axis points east and the positive y-axis points north. (a) If you walk due south, will you start to ascend or descend? ascend descend
Mathematics
1 answer:
Lisa [10]3 years ago
4 0

Answer:

a) "ascend"

Step-by-step explanation:

a)

The equation is  z = 1300-0.005x^2-0.01y^2

This question is asking for the value of the directional derivative in the direction of -j [since south that's y negative]

So, this is the negative of partial derivative of y. Thus we have:

z = 1300-0.005x^2-0.01y^2\\z_y=-0.02y

Now we are at (100,120,1106), we take y value of 120 and put it in the partial:

z_y=-0.02y\\z_y=-0.02(120)\\z_y=-2.4

We take the negative, that is -(-2.4) = 2.4

Since this is positive, we can say the hill is sloping upward at this point, so you will start to ascend.

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saul85 [17]
The way to find the area of a triangle is A=\frac{B*H}{2}
if the base is 3 feet longer then the height we can write it like this B=H+3

now we can add it to our area equation
20=\frac{H(H+3)}{2}
20=\frac{ h^{2} +3h}{2}
40=H^{2}+3H
10\frac{1}{3}=H^{2}
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3 0
4 years ago
Which of the following statements are not true in developing a confidence interval for the population mean?
frutty [35]

Answer:

b) The width of the confidence interval becomes narrower when the sample mean increases.

Step-by-step explanation:

The confidence interval can be calculated as:

\bar{x} \pm \text{Test Statistic}\displaystyle\frac{\sigma}{\sqrt{n}}

a) The width of the confidence interval becomes wider as the confidence level increases.

The above statement is true as the confidence level increases the width increases as the absolute value of test statistic increases.

b) The width of the confidence interval becomes narrower when the sample mean increases.

The above statement is false. As the sample mean increases the width of the confidence interval increases.

c) The width of the confidence interval becomes narrower when the sample size n increases.

The above statement is true as the sample size increases the standard error decreases and the confidence interval become narrower.

8 0
3 years ago
Identify the conic whose equation is given.
irina1246 [14]

Answer:

Hyperbola  

Step-by-step explanation:

The polar equation of a conic section with directrix ± d  has the standard form:

r=ed/(1 ± ecosθ)

where e = the eccentricity.

The eccentricity determines the type of conic section:

e = 0       ⇒ circle

0 < e < 1  ⇒ ellipse

e = 1        ⇒ parabola

e > 1        ⇒ hyperbola

Step 1. <em>Convert the equation to standard form </em>

r = 4/(2 – 4 cosθ)

Divide numerator and denominator by 2

r = 2/(1 - 2cosθ)

Step 2. <em>Identify the conic </em>

e = 2, so the conic is a hyperbola.

The polar plot of the function (below) confirms that the conic is a hyperbola.

5 0
4 years ago
Please any one help me ​
Ulleksa [173]

\qquad\qquad\huge\underline{{\sf Answer}}♨

Since it's a Trapezoid with its non - parallel sides equal to one another,

\qquad \sf  \dashrightarrow \:\angle A + \angle P = 180

[ By forming co - interior angle pair ]

\qquad \sf  \dashrightarrow \:\angle A +100 = 180

\qquad \sf  \dashrightarrow \:\angle A = 180 - 100

\qquad \sf  \dashrightarrow \:\angle A = 80

Now, similarly,

\qquad \sf  \dashrightarrow \:\angle A + \angle R = 180

\qquad \sf  \dashrightarrow \: \angle R + 80 = 180

\qquad \sf  \dashrightarrow \: \angle R  = 100

Similarly,

\qquad \sf  \dashrightarrow \angle K + \angle R = 180

\qquad \sf  \dashrightarrow \angle K + 100 = 180

\qquad \sf  \dashrightarrow \angle K  = 80

3 0
3 years ago
Read 2 more answers
Round 8,349.0054 to the nearest thousands place.
pentagon [3]
To round this we have to go to the thousands place since the thousands place in this question is 8 its closer to 10 so the answer is 10k or 10,000
3 0
3 years ago
Read 2 more answers
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