Answer:
Kindly check explanation
Step-by-step explanation:
Given that:
Cost of owning and operating a printer :
Purchase Cost = $100
Printing per per page = $0.05
Thus, owning and operating cost :
Purchase cost + (Printing per page * number of pages)
Number of pages = p
100 + 0.05p
Service cost :
Amount per page = 0.25
Total revenue = cost per page * number of pages
Total revenue from service =. 0.25p
The equation :
100 + 0.05p = 0.25p ; is the owning and operating cost = total revenue
It gives the equation to calculate the number of pages at which total revenue equals owning and operating cost.
100 + 0.05p = 0.25p
100 =0.25p - 0.05p
100 = 0.20p
p = 100/0.2
p = 500
When number of pages equals 500; the owning and operating cost is equal to the revenue made.
If it's x²y³ then we know it's the second term of the expansion, that known we can use the combination
C(5, 2) = 5!/(2!.3!) = 10
Then if we had something like
(a + b)^5 our second term would be 10a²b³ but as we can see it's "a²"
And in our case we have 2x as a
So we must do 2² too
2² = 4
10 . 4 = 40
Then our second term of the expansion would be
40x²y³
Answer:
m<F = 53
Step-by-step explanation:
Exterior angles thm:
5x - 10 + 3x + 14 = 100
8x + 4 = 100
8x = 104
x = 13
m<F:
3x + 14
3(13) + 14
39 + 14
53
Answer:
x=27
Step-by-step explanation:
Step 1: Simplify both sides of the equation.
5/3x-4/3x-1=8
5
/3
x+ −4
/3
x+−1=8
(5
/3
x+ −4
/3
x)+ (−1) =8 (Combine Like Terms)
1/3x-1 =8
1/3x=9
(1/3 x) x 3 = 3 x 9
x=27
The smallest number of students in the class is the smallest number that is divisible by 2, 3, and 4. You need the least common multiple of 2, 3, and 4.
This is like finding the least common denominator.
Find the prime factors of the three numbers:
2 = 2
3 = 3
4 = 2^2
To find the LCM you need common factors, and not common factors with the larger exponent.
Now single factor is common to all numbers.
There is 2 and 2^2, so use 2^2 since it has the larger exponent.
There is also a 3, so use the 3.
LCM = 2^2 * 3 = 4 * 3 = 12
Mr. Carson's class may have 12 students. 12 is the smallest number of students it can have.